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tatiyna
4 years ago
11

For question 21 ... I need the answer and explain how I got the answer !!!

Mathematics
1 answer:
maks197457 [2]4 years ago
3 0

Answer:

27=3c-3(6-2c)

Open the brackets (multiply 6 and -2c by -3)

27=3c-18+6c

Add 3c and 6c

27=9c-18

Add 18 to both sides

45=9c

Divide by 9

c=5 (45/9)

now to check this just substitute c (5) into the equation

27=(3*5)-18+(6*5)

27=15-18+30

27=30-3

27=27

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What are the factors of -9 that have a sum of 0
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Answer:

3 and -3

Step-by-step explanation:

+3 -3 =0

sum mean adding

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5(x-3) = 2(x+3) solve for x
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Answer:

7

Step-by-step explanation:

5(x - 3) = 2(x + 3)                     Distribute

5x - 15 = 2x + 6                    

    + 15         + 15                     Switch sides to the liked terms

5x = 2x + 6 + 15

-2x  -2x                                   Switch sides to the liked terms

5x - 2x = 6 + 15  

<u>3x</u> = 21                                      Divide

3       3                  

x = 7

4 0
3 years ago
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(2 x 1 )+ (6 x 1/1000) in a standard form
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Answer:

(2 x 1) + (6 x 1/1,000)  

2   + (6)(0.001) 

2   + 0.006  

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Step-by-step explanation:

4 0
2 years ago
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Solve this equation 90x-60y is equal to 68 and 90x-70y is equal to 91​
Tanzania [10]

Answer:

Step-by-step explanation:

90x - 60y = 68.....multiply by -1

90x - 70y = 91

---------------------------

-90x + 60y = -68 (result of multiplying by -1)

90x - 70y = 91

---------------------------add

-10y = 23

y = -23/10 <===

90x - 60y = 68

90x - 60(-23/10) = 68

90x + 138 = 68

90x = 68 - 138

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3 0
4 years ago
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The product of two consecutive odd integers is 782. What are the integers?
Alex Ar [27]

Call the smaller of the two odds = n

Call the next number in the sequence = n + 2

n*(n +2) = 782           Remove the brackets.

n^2 + 2n = 782          Subract 782 from both sides.

n^2 + 2n - 782 = 0    We are going to have to factor this.

Discussion

This problem can't be done the way it is written. The product of an odd integer with another odd integer is and odd integer. There are no exceptions to this. So you need to give a number that has two factors very near it's square root for this question to work.

For example, you could use 783, (which factors) instead of 782 .

Solve

n^2 + 2n - 783 = 0

(n + 29)(x - 27) = 0

<u>Solution One</u>

n - 27 = 0

n = 27

The two odd consecutive integers are 27 and 29.

<u>Solution Two</u>

n + 29 = 0

n = - 29

The two solution integers are -29 and - 27 Notice that - 29 is smaller than - 27.

7 0
4 years ago
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