5b + 29 ≤ -25 is the translation of the phrase "the sum of a number times 5 and 29 is at most -25"
<h3>How to translate an English phrase into an algebraic equation?</h3>
Given the phrase in the question;
The sum of a number times 5 and 29 is at most -25.
First, we translate;
Let the unknown number represented by b.
- A number times 5 ⇒ b × 5 ⇒ 5b
- Sum ⇒ 5b + 29
- Inequality sign for at most -25 ⇒ less than or equal to ⇒ ≤ -25
Now we combine the terms;
5b + 29 ≤ -25
We can go and solve for the unknown number.
5b + 29 ≤ -25
Subtract 29 from both sides
5b + 29 - 29 ≤ -25 - 29
5b ≤ -25 - 29
5b ≤ -54
b ≤ -54/5
Therefore, the translation of the phrase is 5b + 29 ≤ -25.
Learn more about inequality here: brainly.com/question/20383699
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Step-by-step explanation:
H0: u = 44.3
Hi : u# 44.3
Z1-0.05/2
Z1-0.025
Z0.975 = 1.96
Z = x-u/s.d/√n
Z= 44.4 -44.3/2.6/√130
Z = (0.1×11.4018)/2.6
Z=0.44
Since the calcalculated value is less than the table value and does not fall in the rejection region we fail to reject the null hypothesis
Answer:
slope = -4/5 y-intercept = 1
Step-by-step explanation:
y = -4/5+1
Answer:
a) b) the standard deviation and the mean is affected by the conversion factor as well
c) the mean is displaced by b units
Step-by-step explanation:
for a new variable
Y=a*X , where a= constant (conversion factor= 1 kg/2.2 pounds)
then
p(y)= p(a*X) = p(X)
a) mean =μ=E(Y)= ∑ a*X*p(y) = a ∑ X*p(x) = a* E(X)
mean =μ=a*μₓ
b) σ² = ∑ (Y-μ)²* p(y) = ∑ (a*X-a μₓ)²* p(y) = a²*∑ (X-μₓ)²* p(x) = a²*σₓ²
then
standard deviation = σ= √σ²=√(a²*σₓ²) = a*σₓ
standard deviation = σ= a*σₓ
then the standard deviation and the mean is affected by the conversion factor as well
c) nevertheless for a displacement b
Y₂=X + b (b= constant= 50 gr)
p(Y₂)= p(X + b) = p(X)
then
mean =μ=∑ (X-b)*p(y)=∑ X*p(x)- b ∑ p(x) = E(X) -
mean =μ=μₓ - b
then the mean is displaced by b units
