C
6x^2-13X-5=0
(3X+1)(2X-5)
3x-1=0
X=1/3. 2x-5=0. X= 5/2
First you cancel 7 and 28, and 3 and 9, so that leaves you with 4/3 x 15/17, then you cancel 3 and 15 so you get 4x5/17 which should give you 20/17!
Answer:
S'(5,-1), M'(1,-3)
Step-by-step explanation:
So, if the rotation is clockwise, the formula is (x,y)--->(-x,-y).
The original points are, (-1,3) and (-5,1).
Using the formula,
(-1,3) ----> (1,-3)
(-5,1) ----> (5,-1)
For the question in the image, the reflection over the x-axis is..
S'(-5,1) ---> (-5,-1)
M'(1,-3) ---> (-1,-3)
Answer:
The answer to your question is x = 17.32; y = 8.67
Step-by-step explanation:
Process
1.- Use trigonometric functions to find x and y
a) sin Ф = 
Ф = 60°
opposite side = 15
hypotenuse = ?



hypotenuse = 17.32
b) cosФ = 


y = 8.67