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Pepsi [2]
3 years ago
12

What is Log6(13-x)=1

Mathematics
2 answers:
ella [17]3 years ago
4 0

Answer: where there choices?

Step-by-step explanation:

6^1=13-x

6=13-x

-7=-x

x=7

log6 (6) = 1

gogolik [260]3 years ago
4 0

Answer:

I think the answer is 7

Step-by-step explanation:

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Let u = (1, 2 -2), v= (2, 1, 3) and w = j + 4k. a) Find cos theta, where theta is the angle in degrees between u and w.
vodka [1.7K]

Answer: The value of cos theta is -0.352.

Step-by-step explanation:

Since we have given that

\vec{u}=1\hat{i}+2\hat{j}-2\hat{k}\and\\\\\vec{w}=\hat{j}+4\hat{k}

We need to find the cos theta between u and w.

As we know the formula for angle between two vectors.

\cos\ \theta=\dfrac{\vec{u}.\vec{w}}{\mid u\mid \mid w\mid}

So, it becomes,

\cos \theta=\dfrac{2-8}{\sqrt{1^2+2^2+(-2)^2}\sqrt{1^2+4^2}}\\\\\cos \theta=\dfrac{-6}{\sqrt{17}\sqrt{17}}=\dfrac{-6}{17}=-0.352\\\\\theta=\cos^{-1}(\dfrac{-6}{17})=110.66^\circ

Hence, the value of cos theta is -0.352.

8 0
3 years ago
Find all critical points of the given plane autonomous system. (Enter your answers as a comma-separated list.) x′ = x 12 − x − 1
Andru [333]

Answer:

the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

Step-by-step explanation:

To consider the autonomous system

x' =x (12 -x - \dfrac{1}{2})

y' = y( 20 -y - x)

The critical points of the above system can be derived by replacing x' = o and y' = 0.

i.e.

x' =x (12 -x - \dfrac{y}{2}) = 0

\dfrac{x}{2} (24 -2x - y) = 0

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Also

y' = y( 20-y-x) = 0

y( 20 -y - x) = 0

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By solving (1) and (2);

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6 0
2 years ago
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Now it would be
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now just add those two together
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3 years ago
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Step-by-step explanation:

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