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katen-ka-za [31]
3 years ago
8

Please help I will like and brainy

Mathematics
2 answers:
Nitella [24]3 years ago
3 0

What is the value of x in this diagram?


Please help
Tanya [424]3 years ago
3 0

Answer:

Ok ill help u ! What do u need help on?

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3. -Todd orders pictures from a photographer. Each picture costs $7.50. A one-time
faltersainse [42]

Answer:

11

Step-by-step explanation:

85.75 - 3.25 = 82.5

82.5 ÷ 7.50 = 11

7 0
4 years ago
Help plz don't get this
loris [4]
(I see that your concentrating on the task at hand with those YT and fortnite tabs open)

The area of the parallelogram is "base times height," so its 20*8 which is 160.

To find the area of the triangle, we have to find the base which incorporates Pythagorean'd theorem.
100 - 64 = 36, sqrt 36 is 6. So the base of the triangle is 6, the height is 12.6, thus the area is 6.3 * 6, which is 37.8

Adding the two values up, we get 37.8 + 160 = 197.8


3 0
3 years ago
Read 2 more answers
What expression is equivalent to 1/2 divided by 2/3
Maslowich

Answer:

3/4

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Find the area of the trapezoid below to the nearest tenth.
kondor19780726 [428]

Answer:

Area of trapezoid = 67.6 square units

Step-by-step explanation:

Area of a trapezoid is given by the expression,

Area of the trapezoid = \frac{1}{2}(b_1+b_2)h

Here, b_1 and b_2 are the parallel sides of the given trapezoid.

And 'h' = Height between the parallel sides

From the given triangle ABE,

m(∠ABE) = m(∠ABC) - m(∠EBC)

m(∠ABE) = 120° - 90°

               = 30°

By applying cosine rule in the given triangle,

cos(30°) = \frac{\text{Adjacent side}}{\text{Hypotenuse}}

\frac{\sqrt{3} }{2}=\frac{BE}{AB}

\frac{\sqrt{3} }{2}=\frac{BE}{6}

BE = 3\sqrt{3} units

By applying sine rule in ΔABE,

sin(30°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

\frac{1}{2}=\frac{AE}{AB}

\frac{1}{2}=\frac{AE}{6}

AE = 3 units

Length of b_1=BC=10

Length of b_2=AD=(AE+EF+FD) [AE = FD, since given trapezoid ABCD is an isosceles trapezoid]

                b_2=3+10+3

                b_2=16

Height between the parallel sides h=3\sqrt{3}

Area of the trapezoid = \frac{1}{2}(BC+AD)BE

                                    = \frac{1}{2}(10+16)(3\sqrt{3})

                                    = 39\sqrt{3}

                                    = 67.6 square units

8 0
3 years ago
What is another way to write 4 hundreds
hram777 [196]
4 x 100
100 + 100 + 100 + 100
400
four hundred
40 x 10
8 0
3 years ago
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