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9966 [12]
3 years ago
10

Which Greek geometer founded a philosophical society that devoted itself to the study of mathematics

Mathematics
1 answer:
nexus9112 [7]3 years ago
6 0
Pythagoras was the greek geometer.
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Do I have to find a common denominator
antoniya [11.8K]
When it comes to fractions yes you do. But to make it easier just multiply the denominators and that should give u a common denominator, they don't always have to be least common.
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(x - 1)-+ x (1 - x)<br>-<br>-(1+x)<br>--x-1<br>is it correct?<br>​
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Ya i think that it would bee
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Which graph represents this system?<br><br> 2 x minus 5 y = negative 5. y = two-fifths x + 1.
Softa [21]

Answer:

The answer is the first graph.

Step-by-step explanation:

I did it on edge. I got it wrong the first time because I used an answer from this question. Because of that, I reported it. Now I have the correct answer lol.

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Divide 3 by 4, then subtract z from the result
8_murik_8 [283]

Answer:

3/4 = z

Step-by-step explanation:

<u>Step 1:  Convert words into an expression</u>

Divide 3 by 4, then subtract z from the result

3/4 - z

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3/4 - z + z = 0 + z

3/4 = z

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Suppose that the cost of producing x tablets is defined by c(x)= 200 + 10x + 0.2x squared* where x represents the number if tabl
sammy [17]

we are given

C(x)=200+10x+0.2x^2

part-A:

Since, x is number of tablets

C(x) is cost of producing x tablets

so, vertical box is C(x)

so, we write in vertical box is "cost of producing x tablets"

Horizontal box is x

so, we write in horizontal box is "number of tablets"

part-B:

we have to find average on [a,b]

we can use formula

\frac{C(b)-C(a)}{b-a}

we are given point as

a: (15 , 395)

a=15 and C(15)=395

b: (20, 480)

b=20 , C(20)=480

now, we can plug values

=\frac{480-395}{20-15}

=17...........Answer

part-c:

we have to find average on [b,c]

we can use formula

\frac{C(c)-C(b)}{c-b}

we are given point as

b: (20, 480)

b=20 , C(20)=480

c:(25,575)

c=25 , C(c)=575

now, we can plug values

=\frac{575-480}{25-20}

=19..............Answer


5 0
4 years ago
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