To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
15 inches long add 7+5 to get the full total of miles
No there is nothing here please provide answers
Answer:
there are two solutions:
a) 
, and
b) 
Step-by-step explanation:
In the equation: 
, since a perfect square with the unknown "y" is isolated on the left of the equal sign, we start by applying the square root on both sides of the equality, and then on isolating the unknown:
Therefore there are two solutions:
a) , and
b)
Answer:
they are both alike because you're dividing both equations by 2 . in both equations you're trying to get the variable by itself .
they are both different because both of the equations have a different x= . in equation 1 you subtract and in equation 2 you would add .
Step-by-step explanation:
For 2x+4=20 you would make +4 negative 4 to get the variable by itself .
then you'd subtract the numbers 20-4=16
then divide both sides by 2 2÷2 and 16÷2
x=8 is your answer
for 2x-4=20 you would make -4 and make it positive 4 to get the variable by itself
then you'd add the numbers 20+4
then divide both sides by 2 2÷2 and 24÷2
x=12
