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Naily [24]
3 years ago
14

A school library charges a fine of 5 cents on the first day a book is overdue, then doubles the amount owed each day until payme

nt is made. Jada and Juan each had a book that was overdue. Juan returned his book on the 5th day it was overdue. Jada paid a fine that was $2.40 more than Juan’s fine.
Which statement about the overdue books is true?
Jada’s book was overdue by 1 more day than Juan’s book.
Jada’s book was overdue by 2 more days than Juan’s book.
Jada’s book was overdue by 24 more days than Juan’s book.
Jada’s book was overdue by 48 more days than Juan’s book.
Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0

Answer:

Jada's book was overdue by 1 more day than Juan's book.

...................

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what is the exact value of cos(c+d), given sin c=24/25 for c in quadrant 2 and cos d=-3/4 for d in quadrant 3
maksim [4K]

Answer:

1 3/100

21-24squareroot7/100

21

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Step-by-step explanation:

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3 years ago
A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
3 years ago
Please help!! will give brainliest ASAP
soldier1979 [14.2K]

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c = 36.06

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Help me answer this question please
Klio2033 [76]

Answer:

The answer is C.

Step-by-step explanation:

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3 years ago
Read 2 more answers
What is the solution to the equation x – 12 = –3?
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My answer is C
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