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cupoosta [38]
4 years ago
10

Find the y-intercept for the parabola defined by this equation: y= 4x2 – 7x-2

Mathematics
2 answers:
Marina CMI [18]4 years ago
3 0

Answer:

(0,-2); The y-intercept is y=-2.

Step-by-step explanation:

Recall that the y-intercept is simply (0, y). In other words, we simply need to plug zero into the equation to acquire the y.

Thus:

y=4x^2-7x-2

y=4(0)^2-7(0)-2

y=-2

ivann1987 [24]4 years ago
3 0

Answer:

Step-by-step explanation:

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HELPPPP!!!<br> Select the correct answer.<br> Which function is an even function?
jonny [76]

Answer:

C.

Step-by-step explanation:

p(x)=sin(x) is an odd function since sin(-x)=-sin(x).

q(x)=cos(x) is an even function since cos(-x)=cos(x).

r(x)=tan(x) is an odd function since tan(-x)=-tan(x).

s(x)=csc(x) is an odd function since csc(-x)=-csc(x).

So the only contender seems to be C.

Let's check.  To check we have to plug in (-x) in place of (x) and see if we get the same function back since we are looking for an even function.

f(x)=\cos(\frac{5\pi}{4}x)

Replace (x) with (-x):

f(-x)=\cos(\frac{5\pi}{4}(-x)

f(-x)=\cos(\frac{-5\pi}{4}x)

f(x)=\cos(\frac{5\pi}{4}x) since cosine is even; that is cos(-u)=cos(u) where u in this case is \frac{5\pi}{4}x.

So f is even.

7 0
4 years ago
What is the length of TW? Please help me with this.
iragen [17]
TW = 32

Hope this helps!
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=5xy%20%7B%20-%20x%7D%20%5E%7B2%7D%20%7Bt%7D%20%20%2B%202xy%20%2B%203x%20%7B%7D%5E%7B2%7D%20t"
fenix001 [56]

Answer: 7xy + 2x^2t

Step-by-step explanation:

6 0
2 years ago
Help,please, thank you!
guapka [62]

Answer:

x=64°

Step-by-step explanation:

x=180-90-26 (angles on a str line)

=64°

6 0
3 years ago
Read 2 more answers
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
devlian [24]

Answer:

The rocket will reach its maximum height after 6.13 seconds

Step-by-step explanation:

To find the time of the maximum height of the rocket differentiate the equation of the height with respect to the time and then equate the differentiation by 0 to find the time of the maximum height

∵ y is the height of the rocket after launch, x seconds

∵ y = -16x² + 196x + 126

- Differentiate y with respect to x

∴ y' = -16(2)x + 196

∴ y' = -32x + 196

- Equate y' by 0

∴ 0 = -32x + 196

- Add 32x to both sides

∴ 32x = 196

- Divide both sides by 32

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

∴ The rocket will reach its maximum height after 6.13 seconds

There is another solution you can find the vertex point (h , k) of the graph of the quadratic equation y = ax² + bx + c, where h = -\frac{b}{2a} and k is the value of y at x = h and k is the maximum/minimum value

∵ a = -16 , b = 196

∴ h=-\frac{196}{2(-16)}

∴ h = 6.125

∵ h is the value of x at the maximum height

∴ x = 6.125 seconds

- Round it to the nearest hundredth

∴ x = 6.13 seconds

4 0
3 years ago
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