Question

What is the equation of the line in slope-intercept form?

Answer 1

Answer:

y = $\frac{5}{2}$ x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 5) ← 2 points on the line

m = $\frac{5-0}{0-(-2)}$ = $\frac{5}{0+2}$ = $\frac{5}{2}$

The line crosses the y- axis at (0, 5 ) ⇒ c = 5

y = $\frac{5}{2}$ x + 5 ← equation of line

Answer 2

Answer:

y = 2.5x + 5

Step-by-step explanation:

Slope intercept form is y = mx + b, where m is the gradient or slope and b is the y-intercept.

To find the gradient/slope (m), we need to do change in y ÷ change in x.

1. Pick two co-ordinates on the line; (0, 5) and (-2, 0)
2. Subtract the y co-ordinates; 5 - 0 = 5
3. Subtract the x-co-ordinates; 0 - -2 = 2
4. Finally, divide 5 by 2; 5 ÷ 2 = 5/2 or 2.5

Now we have y = 2.5x + b. The y-intercept is simply where the line crosses the y axis (it crosses at 0,5). This means the equation of the line is y = 2.5x + 5.

Hope this helps!