Answer:
Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.
Y = 3x^x (-∞, 0) and (∞, ∞).
Y = 3x^-x (-∞, ∞) and (∞, 0).
Step-by-step explanation:
The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".
When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.
For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.
Here's an image of the graphs:
Thts the answer because 8 is bigger than X the arrow goes to the left because 8 is bigger than numbers 1-7
They are already both positive numbers, so the absolute value of 2 is 2, and the absolute value of 1/3 is 1/3.
15m ^3 - 26m^2 +11m - 4 is the result of the product.
(5m^2 -2m +1)(3m-4)
On opening the bracket, we multiply the terms,
= 15m^3 -6m^2 +3m -20m^2+8m -4
= 15m ^3 - 26m^2 +11m - 4
This is the result of the product
When we mutiply the two equations.