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OleMash [197]
3 years ago
13

Consider the functions f(x) = 5x – 2, g(x) = 5x² + 2 and r(x) = –2x + 4.

Mathematics
2 answers:
Marina86 [1]3 years ago
8 0

Answer:

733 I hope that helps! Sorry if its incorrect

klemol [59]3 years ago
4 0

Answer:

f(-2x+4) = -10x+18

Step-by-step explanation:

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3 7/24 is the answer for your question
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A square patio has a perimeter of (32x+8) feet. What is the length of the patio?
Sonbull [250]

The perimeter of the square patio is the sum of its side lengths

The length of the patio is: 8x + 2

The given parameters are:

\mathbf{Shape = Square}

\mathbf{Perimeter = 32x + 8}

The perimeter of a square is:

\mathbf{Perimeter = 4 \times Length}

So, we have:

\mathbf{4 \times Length = 32x + 8}

Divide both sides by 4

\mathbf{Length = 8x + 2}

Hence, the length of the patio is: 8x + 2

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3 years ago
Help fast thanksddddd​
klasskru [66]

Answer:

2) 10/9 = 1.111111111

3) 1/2 = 0.5

4) 2

5) 3/7 = 0.428571429

6) 4/5 = 0.8

7) 1

8) 42/11 = 3.818181818

9) 5/3 = 1.666666667

10) 7/4 = 1.75

Step-by-step explanation:

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In 1986, the worst nuclear disaster occurred in Chernobyl, USSR, when an explosion at a nuclear power plant released 1000 kg of
Lostsunrise [7]

Considering the function for the remaining amount of cesium in the atmosphere, F(x) = 1000×0.5^(x/30), we have;

First part:

  • The area will be safe again in about 100 years time.

Second part;

  • The y-intercept is at the start of the measurement

Third part;

  • The function is a decay function

<h3>Which method can be used to evaluate the given function?</h3>

First part;

The given function for the remaining amount of cesium is presented as follows;

F(x) = 1000 \times  {0.5}^{ \frac{x}{30} }

When 100 kg. of cesium is remaining, we have;

100= 1000 \times  {0.5}^{ \frac{x}{30} }

Which gives;

\frac{x}{30}  =  \frac{ log(0.1) }{ log(0.5) }

x=  \frac{ log(0.1) }{ log(0.5) }  \times 30 \approx  100

  • Therefore, the area will be safe again in approximately 100 years.

Second part;

The y-intercept is given by the point where <em>x </em>= 0

At the y-intercept, we therefore have;

F(0) = 1000 \times  {0.5}^{ \frac{0}{30} }

  • F(0) = 1000

At the y-intercept, the amount of cesium remaining, F(x) is 1,000, which is the initial amount of cesium.

  • The y-intercept is therefore, at the start of the measurement, where 1000 kg. is present in the atmosphere.

Third part;

The amount of cesium remaining F (x) decreases as the time, <em>x</em>, increases, the function is therefore a decay function.

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Suppose there is 1.1*f drop in temperature for every thousand feet that an airplane climbs in to the sky if the temperature on t
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1.1*11=12.1                        
59.7-12.1=47.6


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3 years ago
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