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Stella [2.4K]
3 years ago
8

A quadrilateral circumscribed about a circle has angles of 80 90 94 and 96. find the measures of the four non overlapping arcs d

etermined by the points of tangency
Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0
For the answer to the question above, <span>the two lines from the 80º angle to the points of tangency:

Try to draw two lines from the points of tangency to the center of the circle:

a quadrilateral with two right angles is formed as you may see.

the angles of a quadrilateral add up to 360º
The center angle is 360º - (90º + 90º + 80º) =100º

Similarly, the angles at the center for other vertices of original quadrilaterals are: 90º, 86º, and 84º
It depends upon the site you measure your arc in, (usual radians) the arcs are π /4 (90º), 7π /30 (84º), 5π /18 (100º) and 43π /180 (86º)</span>
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Gwar [14]

Answer:

y = 4

Step-by-step explanation:

Step 1: Write equation

9/4y - 12 = 1/4y - 4

Step 2: Solve for <em>y</em>

  1. Subtract 1/4y on both sides: 8/4y - 12 = -4
  2. Simplify: 2y - 12 = -4
  3. Add 12 to both sides: 2y = 8
  4. Divide both sides by 2: y = 4

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

9/4(4) - 12 = 1/4(4) - 4

9 - 12 = 1 - 4

-3 = -3

4 0
2 years ago
What is the answer to 8x&lt;6? Please help
Ede4ka [16]

Answer:

x<3/4

Step-by-step explanation:

8x<6

x<6/8

x<3/4

I hope this helps

6 0
3 years ago
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Aleksandr-060686 [28]
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3 years ago
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A line passes through (4, 5) and (8, 9). Which equation best represents the line?
S_A_V [24]
Here, Coordinates: (4, 5) & (8, 9)
Calculation of Slope, m = y2-y1 / x2-x1
m = 9-5 / 8-4
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Now, Take any coordinate: 
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y - 5 = 1(x - 4)
y - 5 = x - 4
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In short, Your Answer would be: y = x + 1

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forsale [732]

<u>Given</u>:

Given that the triangle.

Let the length of the side a be 10 cm.

Let the length of the side b be 13 cm.

Let the measure of ∠C is 105°

We need to determine the area of the triangle.

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

A=\frac{1}{2} a b \ sin \ c

Substituting a = 10, b = 13 and ∠C = 105°, we get;

A=\frac{1}{2}(10)(13) \ sin \ 105

Simplifying, we get;

A=\frac{1}{2}(10)(13)(0.966)

A=\frac{1}{2}(125.58)

A=62.79 \ cm^2

Rounding off to 1 decimal place, we have;

A=62.8 \ cm^2

Thus, the area of the triangle is 62.8 cm²

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