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Stella [2.4K]
3 years ago
8

A quadrilateral circumscribed about a circle has angles of 80 90 94 and 96. find the measures of the four non overlapping arcs d

etermined by the points of tangency
Mathematics
1 answer:
OverLord2011 [107]3 years ago
5 0
For the answer to the question above, <span>the two lines from the 80º angle to the points of tangency:

Try to draw two lines from the points of tangency to the center of the circle:

a quadrilateral with two right angles is formed as you may see.

the angles of a quadrilateral add up to 360º
The center angle is 360º - (90º + 90º + 80º) =100º

Similarly, the angles at the center for other vertices of original quadrilaterals are: 90º, 86º, and 84º
It depends upon the site you measure your arc in, (usual radians) the arcs are π /4 (90º), 7π /30 (84º), 5π /18 (100º) and 43π /180 (86º)</span>
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The polynomial remainder theorem states that the remainder upon dividing a polynomial p(x) by x-c is the same as the value of p(c), so to find p(-10) you need to find the remainder upon dividing

\dfrac{2x^3+14x^2-58x}{x+10}

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