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wariber [46]
3 years ago
7

What is the diameter of a circle with the endpoints (4, 3) and (4, -3)?

Mathematics
1 answer:
Dahasolnce [82]3 years ago
3 0

Given the endpoints of our diameter, we can use the distance formula to find the distance between the points.


Distance Formula:

\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2

(x_2 and x_1 are the x-values of the coordinates and y_2 and y_1 are the y-values of the coordinates)


Inserting our values into the distance formula we can find the length of the diameter:

\sqrt{(4 - 4)^2 + (-3 - 3)^2}

\sqrt{(-6)^2}

\sqrt{36} = \boxed{6}


The diameter of our circle is 6, or choice C.

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Which value of x makes the equation 3x = 36 true?<br> A. 10<br> B. 12<br> C. 14<br> D.16
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Read 2 more answers
In ΔUVW, the measure of ∠W=90°, WV = 39, UW = 80, and VU = 89. What ratio represents the cosine of ∠U?
kumpel [21]

Answer:

cos ∅ = 80/89

Step-by-step explanation:

As required from the question the picture below represent a triangle UVW . The angle W = 90°. The sides WV = 39 , VU = 89 and UW = 80. The triangle forms a right angle triangle .

Such triangle one can establish trigonometric relationship using the SOHCAHTOA principle.

The question requested us to find the ratio that represent the cosine of  ∠U.

The ∠U is represented as ∅ .

Therefore,

cos ∅ = adjacent/hypotenuse

adjacent = 80. The adjacent side is the non hypotenuse side that is next to the given angle.

hypotenuse = 89 . Hypotenuse is the longest side of a right angle triangle and it opposite the right angle.  

cos ∅ = adjacent/hypotenuse

cos ∅ = 80/89

5 0
3 years ago
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