By the law of sines, m∠<em>EFG</em> is such that
sin(m∠<em>EFG</em>) / (8 in.) = sin(m∠<em>G</em>) / (7.5 in)
so you need to find m∠<em>G</em>.
The interior angles to any triangle sum to 180°, so
m∠<em>DEG</em> = m∠<em>D</em> + m∠<em>G</em> + 43°
m∠<em>DEG</em> + m∠<em>D</em> + m∠<em>G </em>= 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°
180° = 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°
137° = 2 (m∠<em>D</em> + m∠<em>G</em>)
68.5° = m∠<em>D</em> + m∠<em>G</em>
But ∆<em>DEG</em> is isosceles, so m∠<em>D</em> = m∠<em>G</em>, which means
68.5° = 2 m∠<em>G</em>
34.25° = m∠<em>G</em>
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Then
sin(m∠<em>EFG</em>) = (8 in.) sin(34.25°) / (7.5 in)
m∠<em>EFG</em> ≈ sin⁻¹(0.600325) ≈ 36.8932°
Answer:
The Area of the sector is: A = 95.4 cm²
Step-by-step explanation:
Given
Central angle Ф = 135°
radius r = 9 cm
To determine
Area of the sector = ?
The Area of the sector can be calculated using the formula
A = Ф/360 × πr²
substitute Ф = 135°, r = 9 and π = 3.14
A = 135/360 × (3.14) (9)²
A = 95.4 cm²
Therefore, the Area of the sector is: A = 95.4 cm²
Step-by-step explanation:
ax=axn to rewrite
3√27x12 as (27x12)1/3
to rewrite
3√(3x^4)3
Pull terms out from under the radical, assuming real numbers.
3X^4
Answer:
Uhm I think you need to like times the 10 to the 56? erm yeaaaaaaa SOrry if you get it wrong
Step-by-step explanation:
Answer:
Your answer should be:
39.5, 45, 8, 38, 10.5, 76, 1, 0.1, 0.0002, 0.5, 3
Apologies if not. Please mark brainliest if correct. Have a nice day!
