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4 years ago

I need help finding area

Mathematics

1 answer:

Pie4 years ago

4 0

You do both of those multiplied by each other

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Let N+2 denote the natural numbers greater than or equal to 2. Let mRn if gcd(m, n) > 1. The binary relation R on N2 is

GaryK [48]

Answer:

a) Reflexive, Symmetric, Not Transitive

Step-by-step explanation:

Given $a\in N+2$ we have that $a\ge 2$ and then $\gcd(a,a)=a\ge 2$ thus the binary relation is reflexive. To show that is symmetric note that for $a,b\in N+2$ we have $\gcd(a,b)=\gcd(b,a)$ which implies the symmetric. In fact, the relation is <u>not</u> transitive, for example note that $\gcd(7,7^2)=7$ and $\gcd(5^2,5)$ but $\gcd(7,5)=1$ .

6 0

4 years ago

What is the solution of the system?

Grace [21]

You can solve the system by isolating the same variable in both equations, then setting those equations equal to each other. For instance, say we isolate y:

$4x+3y=12$
$3y=12-4x$
$y=4- \frac{4}{3} x$

Do the same for the other equation, then set both equations equal to each other. You can then solve for x. Once you have a value for x, you can plug it into either of the original equations and find y!

7 0

3 years ago

Which properties are present in a table that represents an exponential in the form y=b^x when b>1

marissa [1.9K]

Go off bestie yuhhhh

6 0

3 years ago

If ax+3=7-bx, what is x expressed in terms of a and b

ohaa [14]

I hope this helps you

5 0

3 years ago

A potato was launched in the air using a potato gun. The function for the situation was h(t)=-16t^2 +100t+10, where t was the ti

Goshia [24]

Answer:

The height equation is:

h(t)=-16t^2 +100t+10

A) To find the maximum height, we must find the time where the velocity is 0, so we must derive it with respect to the time.

v(t) = -2*16*t + 100 = 0

t = 100/(2*16) = 3.125s

Now we put this time in our height equation:

h(3.125s) = -16*3.125^2 + 100*3.125 + 10 = 166.25 ft.

B) The lowest heigth of the potato will be h = 0ft, when the potato hits the ground.

C) the lowest time that works for that function is t = 0s, when the potato is fired by the gun.

D) the maximum time can be finded when the potato hits the ground, afther that point the equation does not work anymore, let's find it,

h(t) = 0 = -16t^2 +100t+10

we can solve it using Bhaskara's equation:

$t = \frac{-100 +- \sqrt{100^2 +4*16*10} }{-2*16} = \frac{-100 +- 103.2}{-32}$

So the two solutions are:

t = 6.3s

t = -0.1s

We need to chose the positive time, as we already discused that the minimum time that works for the equation is t = 0s.

so here the answer is t = 6.3s

E) the domain is 0s ≤ t ≤ 6.3s

The range is 0ft ≤ h ≤ 166.25 ft.

4 0

3 years ago

I need help finding area​

I need help finding area