What is x*x-2x if x = -3

A storage tank holds 235,500 in^3 of a chemical. The chemical is dispensed to completely fill 25 identical cylindrical container

ololo11 [35]

Volume of a cylinder is given by V = πr^2h

Since the content of the storage tank completely filled the 25 identical cylinders, this means that the volume of the 25 cylinders combined is equal to the volume of the storage tank.

25(πr^2h) = 235,500
πr^2h = 235,500/25 = 9,420
h = 9,420/(3.14 x 5^2) = 9,420/78.5 = 120.

Therefore, the height of the cylinderical containers is 120 in

8 0

3 years ago

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Find three consecutive integers such as two times the first integer, plus three times the second integer, minus the third intege

NikAS [45]

The three consecutive integers are 5, 6, and 7.

What are consecutive integers?

Whole numbers that follow one another without a gap are known as consecutive integers. A few examples of consecutive integers are 15, 16, and 17, 1,2 and 3, and so on.

Finding the Consecutive Integers

Let the three consecutive integers be a, a + 1, and a + 2.

These three consecutive integers are to be such that two times the first integer when added to three times the second integer minus the third integer, it is equal to 21.

⇒ 2a + 3(a+1) - (a+2) = 21

2a + 3a + 3 - a -2 = 21

5a - a + 3 - 2 = 21

4a + 1 = 21

4a = 20

a = 20/4

a = 5

∴ a+1 = 5+1

a+1 = 6

And, a+2 = 5 + 2

a +2 =7

Hence, the three consecutive integers come out to be 5, 6, and 7

Learn more about consecutive integers here:

brainly.com/question/1767889

#SPJ4

8 0

2 years ago

Please select the best answer from the choices provided

Ira Lisetskai [31]

Answer:

The correct answer option is c. $\frac{1}{9a^2}$ .

Step-by-step explanation:

We are given an expression $(27a^{-3})^{-\frac{2}{3} }$ and we are supposed to simplify it.

We can also write $(27a^{-3})^{-\frac{2}{3} }$ as $(\frac{3^3}{a^3} )^{-\frac{2}{3} }$ .

We know the power rule (a^m)^n=a^{mn} which means that to raise a power to a power you need to multiply the exponents.

So multiplying the exponents to get:

$\frac{3^{(3.-\frac{2}{3})} }{a^{(3.\frac{2}{3})} }\\\\\frac{3^{-2}}{a^2}\\ \\\frac{1}{3^2a^2} \\\\\frac{1}{9a^2}$

Therefore, the correct answer option is c. $\frac{1}{9a^2}$ .

4 0

3 years ago

Identify Arithmetic Mean, Geometric Mean and Harmonic Mean from the following averages: 56.4, 59.8 and 55.8

photoshop1234 [79]

If you would like to calculate the arithmetic mean, geometric mean, and harmonic mean from the following averages, you can calculate this using the following steps:

averages: 56.4, 59.8, 55.8
the number of values: 3

arithmetic mean:
(56.4 + 59.8 + 55.8) / 3 = 57.33

geometric mean:
(56.4 * 59.8 * 55.8)^(1/3) = 57.31

harmonic mean:
3 / (1/56.4 + 1/59.8 + 1/55.8) = 57.28

7 0

3 years ago

What is the result of substituting for y in the bottom equation y=x+3 y=x^2+2x-4

8_murik_8 [283]

The solutions are (2.1925, 5.1925) and (-3.1925, -0.1925)

Solution:

Given that,

$y = x + 3 ------- eqn 1\\\\y = x^2 + 2x - 4 ----- eqn 2$

We have to substitute eqn 1 in eqn 2

$x + 3 = x^2 + 2x - 4$

$\mathrm{Switch\:sides}\\\\x^2+2x-4=x+3\\\\\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}\\\\x^2+2x-4-3=x+3-3\\\\\mathrm{Simplify}\\\\x^2+2x-7=x\\\\\mathrm{Subtract\:}x\mathrm{\:from\:both\:sides}\\\\x^2+2x-7-x=x-x\\\\\mathrm{Simplify}\\\\x^2+x-7=0$

$\mathrm{Solve\:with\:the\:quadratic\:formula}\\\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=1,\:c=-7\\\\x =\frac{-1\pm \sqrt{1^2-4\cdot \:1\left(-7\right)}}{2\cdot \:1}$