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GarryVolchara [31]
3 years ago
6

Anyone knows about limitation and continuity?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

If you just plug x=1 in the expression, you can see that, as x approaches 1, the whole expression approaches the following quantity:


\frac{\sqrt{1-y}-2}{2-1} = \frac{\sqrt{1-y}-2}{1} = \sqrt{1-y}-2


Now, how can we find the value of y? We need some additional request. For example, if we knew that this limit had to equal 3, then we would have written


\sqrt{1-y}-2 = 3


and solved for y. But without something like this, we can only compute the limit and get rid of x, but y stays.

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B-3/15=1<br> I have a lot of answers but I don't know which one is correct
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3 years ago
A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a constar
Masteriza [31]

Answer:

  • <u>5.2 kg per month.</u>

<u></u>

Explanation:

The measure of how fast the wrestler gained weight, in kg per month, is the  weight gain rate.

The table is:

Time (months)           Weight (kg)

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The weight gain rate, WGR, for a period may be calculated as:

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  • WGR₂ = [96.2 kg - 88.4 kg] / [3.5 month - 2 month] = 7.8 kg / 1.5 month = 5.2 kg / month.

As you see, the wrestler gained weight at a constant rate of 5.2 kg per month.

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happy to help ya :)

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