Anyone knows about limitation and continuity?
1 answer:
If you just plug x=1 in the expression, you can see that, as x approaches 1, the whole expression approaches the following quantity:
Now, how can we find the value of y? We need some additional request. For example, if we knew that this limit had to equal 3, then we would have written
and solved for y. But without something like this, we can only compute the limit and get rid of x, but y stays.
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Answer:
b = 15.75
Step-by-step explanation:
Lets find the interception points of the curves
36 x² = 25
x² = 25/36 = 0.69444
|x| = √(25/36) = 5/6
thus the interception points are 5/6 and -5/6. By evaluating in 0, we can conclude that the curve y=25 is above the other curve and b should be between 0 and 25 (note that 0 is the smallest value of 36 x²).
The area of the bounded region is given by the integral
The whole region has an area of 250/9. We need b such as the area of the region below the curve y =b and above y=36x^2 is 125/9. The region would be bounded by the points z and -z, for certain z (this is for the symmetry). Also for the symmetry, this region can be splitted into 2 regions with equal area: between -z and 0, and between 0 and z. The area between 0 and z should be 125/18. Note that 36 z² = b, then z = √b/6.
125/18 = b^{1.5}/9
b = (62.5²)^{1/3} = 15.75