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GarryVolchara [31]
3 years ago
6

Anyone knows about limitation and continuity?

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

If you just plug x=1 in the expression, you can see that, as x approaches 1, the whole expression approaches the following quantity:


\frac{\sqrt{1-y}-2}{2-1} = \frac{\sqrt{1-y}-2}{1} = \sqrt{1-y}-2


Now, how can we find the value of y? We need some additional request. For example, if we knew that this limit had to equal 3, then we would have written


\sqrt{1-y}-2 = 3


and solved for y. But without something like this, we can only compute the limit and get rid of x, but y stays.

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Step-by-step explanation:

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