1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
scZoUnD [109]
3 years ago
6

john rode 2 kilometers on his 6ike.his sister sally rode 3000 meters on her bike.who rode the farthest and how much farther did

they ride.
Mathematics
1 answer:
artcher [175]3 years ago
3 0
1 kilometer is 1000 meters.  Therefore, 2 kilometers is 2000 meters.  2000 is greater than 3000, so Sally rode farther by 1000 meter, or 1 kilometer.
You might be interested in
Use the substitution method to solve the system of equations 8x5y=9 y=x+7
Greeley [361]

Answer:

( − 7.00006693 , − 0.00006693 )    ( 0.68099975 , 7.68099975 )

Step-by-step explanation:

3 0
3 years ago
Which equation can be used to calculate the surface area of the triangular prism net show below?
enyata [817]

Given:

Net of a triangular prism

To find:

Which equation can be used to calculate the surface area of the triangular prism.

Solution:

Using formulas:

Area of rectangle = length × width

Area of triangle = \frac{1}{2}\times b\times h

Area of left triangle = \frac{1}{2}\times 5\times 12

Area of right triangle = \frac{1}{2}\times 5\times 12

Area of bottom = 5 × 10

Area of Middle = 12 × 10

Area of top = 13 × 10

Surface area of triangular prism:

Surface area = Area of left triangle + Area of right triangle + Area of bottom + Area of middle + Area of top

                     $=\frac{1}{2}\times 5\times 10+\frac{1}{2}\times 5\times 10+5\times 10+12\times 10+13\times 10

Replace multiplication by brackets.

                     $=\frac{1}{2}(5)(10)+\frac{1}{2}(5)(10)+5( 10)+12( 10)+13( 10)

The equation can be used to calculate surface area of triangular prism is

$\frac{1}{2}(5)(10)+\frac{1}{2}(5)(10)+5( 10)+12( 10)+13( 10).

5 0
3 years ago
Read 2 more answers
Quiz
andreyandreev [35.5K]
I don’t see a pic for this
8 0
3 years ago
Solve the equation sin2∅=2sin∅, domain 0°≤B≤360°
Ann [662]

Answer:

∅ = 90°

Step-by-step explanation:

Given;

sin2∅=2sin∅

sin2∅ = 2sin∅Cos∅

but, Sin²∅ + Cos²∅ = 1

       Cos²∅ = 1 - Sin²∅

       Cos ∅ = √(1 - Sin²∅)

sin2∅=2sin∅ ↓

2sin∅Cos∅ = 2sin∅

2sin∅(√(1 - Sin²∅)) = 2sin∅

Let Sin∅ = P

2P( √(1 - P²)) = 2P

Divide both sides by 2P

√(1 - P²) = 1

Square both sides

1 - P² = 1

P² = 1 - 1

P² = 0

P = 0

Recall, Sin∅ = P

Sin∅ = 0

∅ = Sin ⁻¹(0)

∅ = 90°

5 0
3 years ago
Trinity! Math skills needed here lol
Genrish500 [490]

Answer:

The slope of the line is 6

Step-by-step explanation:

The slope of the line is given by

m=(y2-y1)/(x2-x1)

m =(8-2)/(2-1)

   = 6/1

The slope of the line is 6

5 0
3 years ago
Read 2 more answers
Other questions:
  • Which mathematical figure has length but no beginning or end? A. a point B.a segment C.a line D.a ray
    15·1 answer
  • The triangle shown in the diagram is going to be dilated by a scale factor of 1 3 . What is the length of the new side that corr
    15·1 answer
  • How do u do this question also pls show working out with steps on a piece of paper pls:
    9·1 answer
  • SA is the perpendicular bisector of TR. m∠TSR=120 Which other statement is true?
    10·2 answers
  • Find the value of x. PLEASE HELP!!!
    14·1 answer
  • Which of the following natural landmarks can be found in the Great Plains of Texas O Guadalupe Peak O Sam Houston National Fores
    12·1 answer
  • Why is it important to reconcile your checkbook?
    11·2 answers
  • Lupe had $100 to buy party supplies for her little sister's birthday. She bought 12 bags of party favors and 15 party hats. Each
    15·1 answer
  • Rachel uses 75 inches of ribbon to make 4 bows. She uses the same amount of ribbon to make each bow. 1 foot = 12 inches 1 yard =
    10·1 answer
  • A computer that originally cost $850 is on sale for
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!