Answer:
a mucus or a gelatinous sheath
Explanation:
Most species of cyanobacteria are enclosed in a gelatinous sheath which is made up of proteins.
Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
Answer:
B) a higher protein to lipid ratio.
Explanation:
The cell membrane of eukaryotes is known to be a phospholipid bilayer with embedded proteins. This implies that the first tube will contain a higher amount of lipids.
The membrane of the mitochondria is slightly different from the cell membrane in which its protein to lipid ratio is higher, containing a large number of integral proteins.
