This seems like a lot more work than it is, but here we go
Simplifying<span>8 + -2y = 3y + -2
Reorder the terms: 8 + -2y = -2 + 3y
Solving 8 + -2y = -2 + 3y Solving for variable 'y'. Move all terms containing y to the left, all other terms to the right.
Add '-3y' to each side of the equation. 8 + -2y + -3y = -2 + 3y + -3y Combine like terms: -2y + -3y = -5y 8 + -5y = -2 + 3y + -3y
Combine like terms: 3y + -3y = 0 8 + -5y = -2 + 0 8 + -5y = -2 Add '-8' to each side of the equation. 8 + -8 + -5y = -2 + -8
Combine like terms: 8 + -8 = 0 0 + -5y = -2 + -8 -5y = -2 + -8 Combine like terms: -2 + -8 = -10 -5y = -10
Divide each side by '-5'. y = 2
Simplifying y = 2</span><span>
</span>
Answer:
6 in
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Juanita and samuel are planning a pizza party. they order a rectangle sheet pizza that measures 21 inches by 36 inches.? they tell the pizza maker not to cut it because they want to cut it themselves. All pieces of pizza must be square with none left over. what is the side length of the largest square pieces into which juanita and samuel can cut the pizza?
First we need to calculate the area of the rectangular pizza.
Area of a rectangle = Length × Breadth
Area of the rectangular pizza= 21×36
Area of the rectangular pizza = 756in²
Next is to equate the area of the rectangle to the area of a square.
Area of a square = L²
Therefore L² = 756
L = √756
L = √36×21
L = √36×√21
L = 6√21
This means that the length if the largest square they can cut is 6in (ignoring the irrational part of the length gotten)
Answer:
The roots are 
, which is given by option C.
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
In this question, we have that:
Which is a quadratic equation with 
. So
So the roots are , which is given by option C.
The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement. Yes, there is a "relationship" regarding the tangent of the two acute angles (A and B) in a right triangle.
