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liberstina [14]
2 years ago
8

A boat is anchored 2 km south of a lighthouse. The town of Beachton is Located 17 Km East of the lighthouse. What is the distanc

e from the boat to Beachton. Round to the nearest tenth. Please Help!!
Mathematics
2 answers:
Goryan [66]2 years ago
8 0

Answer: the answer is 27.1 km

Step-by-step explanation:

mina [271]2 years ago
3 0

Answer:

the answer is 17.1

Step-by-step explanation:

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For which positive integer values of $k$ does $kx^2+20x+k=0$ have rational solutions? Express your answers separated by commas a
Musya8 [376]

Answer:

-10,10

Step-by-step explanation:

The given quadratic equation is

k {x}^{2}  + 20x + k = 0

The discriminant of this equation is given by;

D =  {b}^{2}  - 4ac

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For rational solutions, the discriminant must be zero.

{20}^{2}  - 4 \times k \times k = 0

Simplify to get:

400 - 4  {k}^{2}  = 0

This implies that:

400  = 4  {k}^{2}

100 =  {k}^{2}

Take square root to get:

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2 years ago
If y=8 when x =3, find y when x=45
Art [367]
Let's make things easier by simplifying things.

y = 8 and x = 3 is more likely to be understood as a ratio. So for the rest of the answer, their relationship would be represented as y:x

Thus: y:x = 8:3

The problem would be finding y when x = 45

Let us proceed on using the previous equation and substitute x with 45 which would look like this:

y:45 = 8:3

Ratios can also be expressed as fractions which would make things more understandable and easy to solve. So the new form of our equation would be like this:

y/45 = 8/3

Then we proceed with a cross multiplication where the equation becomes like as what is shown below:

3y = 45 * 8

From there, you can solve it by multiplying 45 and 8 then dividing the product with 3 to get y

3y = 360

y = 120

Another way of looking at the problem, especially problems like these, is to take the whole question or statement as an equation. it would probably look like this:

y = 8 when x = 3 : y = ? when x = 45

This would make you understand what approach you can use to solve the given problem.
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