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3 years ago

Is 66mm greater than 6cm

Mathematics

1 answer:

vivado [14]3 years ago

4 0

Heres what u need to know. C:

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Find the difference <br><br><br>-2(c + 2.5) - 5(1.2c + 4)

Vikentia [17]

Answer:
|−∣=7
Explanation:

∣−∣
= |(-2-5)|
= |-2-5|
= | -7|=7

8 0

2 years ago

which is the slope of a line that is perpendicular to the line that passes through the points (29, 24) and (3, 4)?

Nataliya [291]

Answer:

26/20

Step-by-step explanation:

y2-y1 divided by x2-x1

4-24= -20

3-29= -26

-20/-26= m

perpendicular means to switch the numbers and change the sign

a perpendicular slope to -20/-26 is 26/20.

3 0

2 years ago

Combine the x tiles to get

Ivenika [448]

Pls give the question to expect that u get answers from others

Thank u

6 0

3 years ago

Johnny is starting a zoo. His favorite animals are lions, tigers and snakes. These are the only animals in the zoo and he has th

Tatiana [17]

The total number of snakes in the zoo is 10.

<h3>How to use ratio to find the number of snake?</h3>

The number of snake can be found using ratio as follows:

The animals in the zoo are lions, tigers and snakes and he has them in the ratio of 5 : 3 : 2. The total animal is 50 animals.

Therefore,

total snakes = 2 / 10 × 50

total snakes = 100 / 10

total snakes = 10

Therefore, the total number of snakes in the zoo is 10.

learn more on ratio here: brainly.com/question/14524026

#SPJ1

6 0

1 year ago

PLEASE HELP.

krek1111 [17]

Answer:

Part a) The radii are segments AC and AD and the tangents are the segments CE and DE

Part b) $DE=4\sqrt{10}\ cm$

Step-by-step explanation:

Part a)

we know that

A <u>radius</u> is a line from any point on the circumference to the center of the circle

A <u>tangent</u> to a circle is a straight line which touches the circle at only one point. The tangent to a circle is perpendicular to the radius at the point of tangency.

In this problem

The radii are the segments AC and AD

The tangents are the segments CE and DE

Part b)

we know that

radius AC is perpendicular to the tangent CE

radius AD is perpendicular to the tangent DE

CE=DE

Triangle ACE is congruent with triangle ADE

Applying the Pythagoras Theorem

$AE^{2}=AC^{2}+CE^{2}$

substitute the values and solve for CE

$14^{2}=6^{2}+CE^{2}$

$CE^{2}=14^{2}-6^{2}$

$CE^{2}=160$

$CE=\sqrt{160}\ cm$

$CE=4\sqrt{10}\ cm$

remember that

CE=DE

$DE=4\sqrt{10}\ cm$

7 0

3 years ago