Answer:
The horizontal distance from the plane to the person on the runway is 20408.16 ft.
Step-by-step explanation:
Consider the figure below,
Where AB represent altitude of the plane is 4000 ft above the ground , C represents the runner. The angle of elevation from the runway to the plane is 11.1°
BC is the horizontal distance from the plane to the person on the runway.
We have to find distance BC,
Using trigonometric ratio,
Here, 
,Perpendicular AB = 4000
Solving for BC, we get,
(approx)
(approx)
Thus, the horizontal distance from the plane to the person on the runway is 20408.16 ft
Answer:
2.646
Step-by-step explanation:
You have to 6 to the 1 and then take the square root of the number which is seven leaving you with 2.646
Х is the first <span>integer
</span>(x+1) is the second integer
x + x + 1 = -49
2x + 1 = - 49
2x = -49 - 1
2x = -50
x = -25 first integer
-25 + 1 = -24 second integer
Answer: -25 and -24
The exponential function that describes the graph is 
The standard form of an exponential function is expressed as 
a is the y-intercept
(x, y) is the point on the graph
Given the following expression
a = 7
(x, y) = (4, 112)
Substitute the given values into the exponential equation
![y = ab^x\\112=7\cdot b^4\\b^4 = \frac{112}{7}\\b^4= 16\\b =\sqrt[4]{16}\\b = 2](https://tex.z-dn.net/?f=y%20%3D%20ab%5Ex%5C%5C112%3D7%5Ccdot%20b%5E4%5C%5Cb%5E4%20%3D%20%5Cfrac%7B112%7D%7B7%7D%5C%5Cb%5E4%3D%2016%5C%5Cb%20%3D%5Csqrt%5B4%5D%7B16%7D%5C%5Cb%20%3D%202)
Get the required exponential equation
Recall that , hence the required equation will be
Learn more here: brainly.com/question/19245707
