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AnnyKZ [126]
3 years ago
8

Asia and taryn each had the same amount of money. after asia spent $14 and taryn spent $22, the ratio of asia's money to taryn's

money was 4 to 3. how much money did each girl have at first
Mathematics
1 answer:
blagie [28]3 years ago
7 0

It is given in the question that

Asia and taryn each had the same amount of money. after asia spent $14 and taryn spent $22, the ratio of asia's money to taryn's money was 4 to 3.

Let , initially, they both have $x each .

So according to the given question ,

\frac{x-14}{x-22} = \frac{4}{3}

Cross multiplication

3(x-14) = 4(x-22)
\\
3x-42 = 4x-88
\\
88-42 = 4x-3x
\\
x = 46

Therefore , initially, they both have $46 each .

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Answer:

(5v + 2)(v - 5)

Step-by-step explanation:

Hello!

The expression is written in the form of ax^2 + bx + c

Let's factor by grouping:

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-25 and 2 work for this.

Expand and factor:

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Step-by-step explanation:

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You want to give your friend a soccer ball for a gift. The soccer ball has a
Ede4ka [16]

Answer:

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All the best !!

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