Answer:
See below
Step-by-step explanation:
a. How fast does the plane fly during the first leg of the trip?
b. How fast does the plane fly during the last leg of the trip?
c. What system of equations might be helpful in this scenario?
<u>s - speed of the plane, w - speed of the wind, equations:</u>
d. Solve this system of equations using the best method.
Add the equation together to get:
- 2s = 1100 ⇒ s = 550 mph
- w = 550 - 430 = 120 mph
e. How fast is the wind?
f. How fast does the plane fly without any wind?
I’m sorry i can’t help :,( sending good grades for your last days of school!
Answer:
x = 5/39
, y = 539/39
Step-by-step explanation:
Solve the following system:
{y - 2.5 x = 13.5
12.25 x - y = -12.25
In the first equation, look to solve for y:
{y - 2.5 x = 13.5
12.25 x - y = -12.25
y - 2.5 x = y - (5 x)/2 and 13.5 = 27/2:
y - (5 x)/2 = 27/2
Add (5 x)/2 to both sides:
{y = 1/2 (5 x + 27)
12.25 x - y = -12.25
Substitute y = 1/2 (5 x + 27) into the second equation:
{y = 1/2 (5 x + 27)
1/2 (-5 x - 27) + 12.25 x = -12.25
(-5 x - 27)/2 + 12.25 x = 12.25 x + (-(5 x)/2 - 27/2) = 9.75 x - 27/2:
{y = 1/2 (5 x + 27)
9.75 x - 27/2 = -12.25
In the second equation, look to solve for x:
{y = 1/2 (5 x + 27)
9.75 x - 27/2 = -12.25
9.75 x - 27/2 = (39 x)/4 - 27/2 and -12.25 = -49/4:
(39 x)/4 - 27/2 = -49/4
Add 27/2 to both sides:
{y = 1/2 (5 x + 27)
(39 x)/4 = 5/4
Multiply both sides by 4/39:
{y = 1/2 (5 x + 27)
x = 5/39
Substitute x = 5/39 into the first equation:
{y = 539/39
x = 5/39
Collect results in alphabetical order:
Answer: {x = 5/39
, y = 539/39
Answer:
no identity will escape! I know where you live
Answer:
5.5
Step-by-step explanation:
5.5/10 = 8.5/(y+10)
if you solve it, it'll look like
y = 60/11
which is approximately 5.5
Answered by GAUTHMATH
