Answer:
Infinitely many solutions
Step-by-step explanation:
V=(1/3)hpir^2
lets say this is original, undoubled volume
so o=v=(1/3)hpir^2
so for new volume, or n, that is r to 2r, doubled radius
n=(1/3)hpi(2r)^2
n=(1/3)hpi4r^2
n=4((1/3)hpir^2)
remmember that o=(1/3)hpir^2
n=4(o)
it is 4 times the old one
The answer is 3x+15
You multiply the x and 5 by 3 to get 3x and 15
Depends on how much space you have on your device
A cylinder. If you imagine and draw it out it looks like a cylinder.
