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larisa [96]
2 years ago
6

Mercury is the closest planet to the sun at a distance of 36 million miles. The closest star to the sun is Proxima Centauri, whi

ch is 4.24 light years away. A light year is 5.9 x 10 to the 12th power. How many miles from the sun is Proxima Centauri?
Mathematics
1 answer:
borishaifa [10]2 years ago
7 0

Answer:

Proxima Centauri is 2.478 x 10¹³ miles from Sun.

Explanation:

 Distance of Proxima Centauri to sun = 4.24 light years

 1 light year = 5.9 x 10¹² miles.

 Distance of Proxima Centauri to sun in miles = Distance in light years x 5.9 x 10¹² miles

 So, Distance of Proxima Centauri to sun in miles = 4.2 x 5.9 x 10¹² miles

                                                                               = 2.478 x 10¹³ miles

  So Proxima Centauri is 2.478 x 10¹³ miles from Sun.

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I really need help!!!!
Brilliant_brown [7]
Check out the attached image for the answers. 

-----------------------

Statement 2 is blank, but it has the reasoning "Corresponding angles postulate"
Because BD || AE, we know that the corresponding angles are congruent. 
One pair of corresponding angles is angle 1 and angle 4. This is because they are on the same side of the transversal AC and they are both above their parallel line counter-part. Similarly, angle 2 and angle 3 are another corresponding pair.
So you'll have "angle1=angle4, angle3=angle2" in the first blank slot

-----------------------

Reason 3 is blank. The statement is that triangle ACE is similar to triangle BCD. The reason why the are similar is the AA (angle angle) similarity postulate. This says that if you know two pairs of angles are congruent, then the triangles are similar. The two pairs of angles were mentioned back on the previous line (line 2)
So you'll put "Angle-Angle Similarity Postulate" in the second blank.

-----------------------

Look at the line just above the last line. Here we have
1 + (BA/CB) = 1 + (DE/CD)
If we subtract 1 from both sides, we end up with,
BA/CB = DE/CD
which is what will go in the last blank space

Side Note: The last statement will always be what you want to prove. So you can just look at the very top of the problem where it says "Prove:" under the "Given" part. Then just copy/paste the statement you want to prove, which in this case is BA/CB = DE/CD

4 0
3 years ago
What is the answer to this ?
harina [27]

Answer:

The answer is option 1.

Step-by-step explanation:

In order to solve x, you have to make x the subject, by multiplying each sides by 5, to get rid of 5 on the left side.

\frac{x}{5}  = 8

\frac{x}{5}  \times 5 = 8 \times 5

x = 40

5 0
3 years ago
1. What is the measure of angle PSQ?<br><br> 80°<br> 140°
Anna11 [10]
140 degrees because an angle of a circle is 360 degrees and you can subtract these angles from it to get 140 degrees
3 0
2 years ago
Read 2 more answers
The area of a rectangle has decreased by 2%.
MissTica

Answer:

The other side was decreased to approximately .89 times its original size, meaning it was reduced by approximately 11%

Step-by-step explanation:

We can start with the basic equation for the area of a rectangle:

l × w = a

And now express the changes described above as an equation, using "p" as the amount that the width is changed:

(l × 1.1) × (w × p) = a × .98

Now let's rearrange both of those equations to solve for a / l.  Starting with the first and easiest:

w = a/l

now the second one:

1.1l × wp = 0.98a

wp = 0.98a / 1.1l

1.1 wp / 0.98 = a/l

Now with both of those equalling a/l, we can equate them:

1.1 wp / 0.98 =  w

We can then divide both sides by w, eliminating it

1.1wp / 0.98w = w/w

1.1p / 0.98 = 1

And solve for p

1.1p = 0.98

p = 0.98 / 1.1

p ≈ 0.89

So the width is scaled by approximately 89%

We can double check that too.  Let's multiply that by the scaled length and see if we get the two percent decrease:

.89 × 1.1 = 0.979

That should be 0.98, and we're close enough.  That difference of 1/1000 is due to rounding the 0.98 / 1.1 to .89.  The actual result of that fraction is 0.89090909...  if we multiply that by 1.1, we get exactly .98.

6 0
2 years ago
The area of two rectangles is given by he functions: area of a rectangle A:f(x)= 4x2+6x area of rectangle B:g(x)=3x2-x Which fun
dusya [7]

Answer:

x^2+7x if you are asked to find the difference of a function f and function g

Step-by-step explanation:

We are asked to A-B or f(x)-g(x).

(4x^2+6x)-(3x^2-x)

4x^2+6x-3x^2+x

The like terms I'm going to pair up.

4x^2-3x^2+6x+x

1x^2          +7x

x^2            +7x

The answer is x^2+7x

7 0
3 years ago
Read 2 more answers
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