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lianna [129]
3 years ago
8

Which of the following elements would be the most reactive?

Chemistry
1 answer:
Tanya [424]3 years ago
4 0

Answer:

iodine

Explanation:

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Once the concentration of the common ion is increased: Select the correct answer below: the solubility of the ionic solid increa
Vaselesa [24]

Answer:

the solubility of the ionic solid decreases

Explanation:

If a salt MX is added to an aqueous solution containing the solute AX, the X^- ion is common to both of the salts. The presence of X^- in the solution will suppress the dissolution of AX compared to the solubility of AX in pure water. This observation is known as common ion effect in chemistry.

The origin of common ion effect is based on Le Chatelier's principle. The addition of a solute will drive the equilibrium position towards the left hand side.

3 0
3 years ago
Give chemical equation representing ionisation of carbonic acid
boyakko [2]

Answer:

HCO3− + OH− ⇌ CO32− + H2O

hope it helps!!!!

6 0
3 years ago
A sample of helium gas has a pressure of 1.5 atm at 23 C. At what Celsius
Nina [5.8K]

Answer:

180.87 °C

Explanation:

Applying pressure law,

P/T = P'/T'..................... Equation 1

Where P = Initial pressure of helium gas, T = Initial Temperature of helium gas, P' = Final Pressure of helium gas, T' = Final Temperature of helium gas

Make T' the subject of equation 1

T' = P'T/P......................... Equation 2

From the question,

Given: P = 1.5 atm, P' = 2.3 atm, T = 23°C = (23+273)K = 296 K

Substitute these values into equation 2

T' = (2.3×296/1.5)

T' = 680.8/1.5

T' = 453.87 K

T' = 453.87-273

T' = 180.87°C

3 0
3 years ago
Which group has 4 valence electrons
Rama09 [41]
Group 14: Carbon family has valence electrons. 
4 0
4 years ago
Read 2 more answers
Sulfur dioxide and oxygen react to form sulfur trioxide, like this: (g) (g) (g) Also, a chemist finds that at a certain temperat
OLEGan [10]

Answer:

Kp=9.2x10^{-3}

Explanation:

Hello!

In this case, for the undergoing chemical reaction at equilibrium:

2SO_2(g)+O_2(g)\rightleftharpoons 2SO_3(g)

Which means that pressure-based equilibrium constant is computed via the following equilibrium expression:

Kp=\frac{p_{SO_3}^2}{p_{SO_2}^2p_{O_2}}

Thus, by plugging in the given pressures at equilibrium, the required Kp turns out:

Kp=\frac{55.0^2}{70.2^2*66.7}\\\\Kp=9.2x10^{-3}

Best regards!

3 0
3 years ago
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