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Mademuasel [1]
4 years ago
14

If you want to increase the gravitational force between two objects, what would you do

Chemistry
2 answers:
nadezda [96]4 years ago
6 0
There are two things that could be done. The first is to increase the mass of the objects. The second is to decrease the distance between the center of masses of the objects.
mart [117]4 years ago
3 0

Answer:

If we want to increase this force, we can increase the mass of the objects, but it is more effective to reduce the distance between them.

Explanation:

The gravitational force exerted between two bodies depends on the distance between them and the mass of each of them. The formula is as follows:

F_{g}= -G * \frac{M * m}{r^{2} }

F_{g}: Gravitational force.

G: Universal gravitation constant.

M and m: Masses of the interacting bodies.

r: Distance separating the bodies.

We observe that if M or m increases, F_{g} also increases. On the other hand, if r decreases, this causes F_{g} to increase as well.

Have a nice day!

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7 0
3 years ago
Read 2 more answers
Two linear hydrocarbons, Hexane (C6H14) and Heptane (C7H16), form pretty much an ideal solution at any composition. A solution i
Anettt [7]

Answer:

y_{C_6H_{14}}=0.92

Explanation:

Hello,

At first, we compute liquid-phase molar fractions:

n_{C_6H_{14}}=463.96 g*\frac{1mol}{86g} =5.3949molC_6H_{14}\\n_{C_7H_{16}}=667.71 g*\frac{1mol}{100g} =6.6771molC_7H_{16}\\x_{C_6H_{14}}=\frac{5.3949}{5.3949+6.6771} =0.447\\x_{C_7H_{16}}=1-x_{C_6H_{14}}=0.553

Now, by means of the fugacity concept, for hexane, for instance, we have:

f_{C_6H_{14}}^V=f_{C_6H_{14}}^L\\y_{C_6H_{14}}p_T=x_{C_6H_{14}}p_{C_6H_{14}}

In this manner, at 25 °C the vapor pressure of hexane and heptane are 0.198946 atm and 0.013912 atm repectively, thus, the total pressure is:

p_T=x_{C_6H_{14}}p_{C_6H_{14}}+x_{C_7H_{16}}p_{C_7H_{16}}\\p_T=0.447*0.198946 atm +0.553*0.013912 atm=0.096622atm

Finally, from the hexane's fugacity equation, we find its mole fraction in the vapour as:

y_{C_6H_{14}}=\frac{x_{C_6H_{14}}p_{C_6H_{14}}}{p_T}=\frac{0.447*0.198946 atm}{0.096622atm} \\y_{C_6H_{14}}=0.92

Best regards.

3 0
3 years ago
Read 2 more answers
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