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photoshop1234 [79]
3 years ago
12

aladdin has 12 gold coins in his magic bag. genie tells him that for every 100 gold coins he has in his magic bag, he will get 2

5 extra gold coin every year. How many years later will aladdin have 21 gold coins in his bag?
Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

In 3 years.

Step-by-step explanation:

For every 100 gold coins Aladdin has in his magic bag, he will get 25 extra gold coin every year.

This means that for every 100\div 25=4 gold coins Aladdin will get 25\div 25=1 extra gold coin every year.

Aladdin has 12 gold coins in his magic bag. Then after first year, he will get 12\div 4=3 extra gold coins this year. In total he will have 12+3=15  gold coins.

Aladdin has 15 gold coins in his magic bag. Then after second year, he will get 15\div 4=3\ (remainder \ 3) extra gold coins this year. In total he will have 15+3=18  gold coins.

Aladdin has 18 gold coins in his magic bag. Then after third year, he will get 18\div 4=4\ (remainder \ 2) extra gold coins this year. In total he will have 18+4=22>21  gold coins.

Hence, in three years, Aladdin will have 21 gold coins.

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Which equation shows an example of the associative property of addition?
Nat2105 [25]

The associative property states that we can regroup the terms of an expression and obtain the same result.

We have then:

a + (b + c) = (a + b) + c

The expression that complies with this property is given by:

(-4 + i) + 4i = -4 + (i + 4i)

Answer:

An equation that shows an example of the associative property of addition is:

a. (- 4 + i) + 4i = -4 + (i + 4i)

6 0
3 years ago
Read 2 more answers
Can someone please help me out with this I’ve been stuck on it
Sonja [21]

Answer:

-3

Step-by-step explanation:

-9+6

=6-9

=-3

6 0
4 years ago
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Solve quickly please.
lys-0071 [83]

Find the change between the first two sets:

12-9 = 3

14.4 - 10.8 = 3.6

3.6/3 = 1.2

Now find the change between the last two sets:

12 - -3 = 15

14.4 - 3.6 = 10.8

10.8/15 = 0.72

1.2 does not equal 0.72 so the answer is No

4 0
3 years ago
I need help on this ik ik im stupid
ziro4ka [17]

Answer:

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8 0
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Let a and b be real constants such that \[x^4 ax^3 3x^2 bx 1 \ge 0\]for all real numbers x. Find the largest possible value of a
tatiyna

Answer:

Infinity

Step-by-step explanation:

Since x^4 ax^3 3x^2 bx 1 \ge 0 for all real numbers x, this property is also true for x=1, which tells us that

1^4 a1^3 3\cdot1^2 b\cdot 1=3ab\ge0

On the other hand, note that for all real numbers x, it holds that

x^4x^3x^2x\ge 0

Therefore, if

3ab\geq0

we have tat

3ab x^{4}x^{3}x^{2}x^{1}1=x^4ax^3 3x^2bx1\ge0

The last reasoning tells us that the property x^4 ax^3 3x^2 bx 1 \ge 0 holds for all real numbers x if an only if ab\ge0

Therefore, we can choose arbitrary constants a and b as long as

ab\ge0

We can choose a and b such that both positive, both negative or one of the two constants is equal two zero. In the first two cases

a^2b^2  

can get as big as we want, depending on the constants, and we are done.

8 0
3 years ago
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