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3 years ago

Pls help me do you know the answer let me know

Mathematics

2 answers:

sergij07 [2.7K]3 years ago

8 0

Answer:

I'm so sorry I have no idea seems so so complicated

Step-by-step explanation:

But I think you would need a specific equation for it and substitute numbers in it.

FrozenT [24]3 years ago

3 0

Answer:

Are you telling us to answer it all?

Step-by-step explanation:

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2 years ago

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2 years ago

Solve the following triangle. Given A=51 degrees b=40 c=45

STALIN [3.7K]

Answer:

$a=36.87\ units$

$B=57.47^o$

$C=71.53^o$

Step-by-step explanation:

step 1

Find the length side a

Applying the law of cosines

$a^2=b^2+c^2-2(b)(c)cos(A)$

substitute the given values

$a^2=40^2+45^2-2(40)(45)cos(51^o)$

$a^2=1,359.4466$

$a=36.87\ units$

step 2

Find the measure of angle B

Applying the law of sines

$\frac{a}{sin(A)} =\frac{b}{sin(B)}$

substitute the given values

$\frac{36.87}{sin(51^o)} =\frac{40}{sin(B)}$

$sin(B)=\frac{sin(51^o)}{36.87}{40}$

$B=sin^{-1}(\frac{sin(51^o)}{36.87}{40})=57.47^o$

step 3

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

substitute the given values

$51^o+57.47^o+C=180^o$

$108.47^o+C=180^o$

$C=180^o-108.47^o=71.53^o$

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3 years ago

What is the solution set of the quadratic equation 8x2 +2x +1 =0?

Sidana [21]

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x_{12}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}=\frac{-2\pm \sqrt{2^2-4\cdot 8 \cdot 1}}{2\cdot 8}=\\\\
=\frac{-2\pm \sqrt{4-32}}{16}=\frac{-2\pm \sqrt{-28}}{16}=\frac{-2\pm \sqrt{4\cdot 7\cdot(-1)}}{16}=\\\\
=\frac{-2\pm 2i\sqrt{7}}{16}=\frac{-1\pm i\sqrt{7}}{8}= -\frac{1}{8}\pm \frac{\sqrt{7}}{8}i\\\\
x_1 = \boxed{-\frac{1}{8}+ \frac{\sqrt{7}}{8}i}\\\\
x_2 = \boxed{-\frac{1}{8}- \frac{\sqrt{7}}{8}i}\\\\
x_1,~x_2~\in \mathbb{C}$

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3 years ago