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2 years ago

The measure of an angle is 22° greater than it’s complement. Find the angle

Mathematics

1 answer:

mamaluj [8]2 years ago

7 0

Answer:

Step-by-step explanation:

Let the angle be " x ".

Complement of the angle = ( x - 22 )

To find : x = ?

x + x - 22 = 90

2x - 22 = 90

2x = 90 + 22

2x = 112

x = 112 / 2

x = 56

Therefore, the angle is 56.

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The net of a pyramid is shown below:

Stells [14]

Answer:

245 square inches

Step-by-step explanation:

4(1/2×7×14)+(7×7)

4 0

2 years ago

If a system of linear equations has no solution, what do you know about the slopes and y-intercepts of the graphs of the equatio

Nata [24]

Answer:

B. The slopes of the graphs are the same and the y-intercepts of the graphs are different

Step-by-step explanation:

The lines will also be parallel

7 0

2 years ago

There are 135 people in a sport centre. 73 people use the gym. 59 people use the swimming pool. 31 people use the track. 19 peop

Sonbull [250]

Answer:

24 people

Step-by-step explanation:

((The numbers are up there, so I am not going to define each variable.))

For starters, there is no overlap between the double facilities groups, except the triple facility users, so:

19 + 9 + 16 - 4 = 40 people

Since there is overlap between single and double groups, you will need to subtract, so:

Gym: 73 - 19 - 16 = 38

Pool: 59 - 19 - 9 = 31

Track: 31 - 9 - 16 = 6

Total for 1 facility: 38 + 31 + 6 - 4 = 71 people

((Minus 4 because the 4 triple facility users overlap the double facility users (problem is in layers: layer 1 minus layer 2, then minus layer 3).))

Next, add the totals:

71 + 40 = 111 people (using facilities)

135 - 111 = 24 people (who didn't use any)

(((I'm not 100% sure on this answer, so if someone could check my work, that would be much appreciated.)))

4 0

3 years ago

PLEASE PLEASE PLEASE HELP ME

lubasha [3.4K]

Answer:

CE = 17

Step-by-step explanation:

∵ m∠D = 90

∵ DK ⊥ CE

∴ m∠KDE = m∠KCD⇒Complement angles to angle CDK

In the two Δ KDE and KCD:

∵ m∠KDE = m∠KCD

∵ m∠DKE = m∠CKD

∵ DK is a common side

∴ Δ KDE is similar to ΔKCD

∴ $\frac{KD}{KC}=\frac{DE}{CD}=\frac{KE}{KD}$

∵ DE : CD = 5 : 3

∴ $\frac{KD}{KC}=\frac{5}{3}$

∴ KD = 5/3 KC

∵ KE = KC + 8

∵ $\frac{KE}{KD}=\frac{5}{3}$

∴ $\frac{KC+8}{\frac{5}{3}KC }=\frac{5}{3}$

∴ $KC + 8 = \frac{25}{9}KC$

∴ $\frac{25}{9}KC - KC=8$

∴ $\frac{16}{9}KC=8$

∴ KC = (8 × 9) ÷ 16 = 4.5

∴ KE = 8 + 4.5 = 12.5

∴ CE = 12.5 + 4.5 = 17

7 0

2 years ago

Tan9 - tan27 - tan63 + tan 81 = ?

ludmilkaskok [199]

Tan9−tan27−tan63−tan81
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8 0

2 years ago