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3 years ago

6

tim saw some monkey's sitting in trees at the zoo there were monkeys sitting in each tree. there were 24 monkeys in all. how man

y trees were there?

1 answer:

telo118 [61]3 years ago

4 0

Answer:

there needs to be more detail

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F(x)=lx+4l+3 how do u do it

dybincka [34]

Answer:

implifying

f(x) = lx + 4l + -3

Multiply f * x

fx = lx + 4l + -3

Reorder the terms:

fx = -3 + 4l + lx

Solving

fx = -3 + 4l + lx

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Divide each side by 'x'.

f = -3x-1 + 4lx-1 + l

Simplifying

f = -3x-1 + 4lx-1 + l

Reorder the terms:

f = l + 4lx-1 + -3x-1

Step-by-step explanation:

4 0

2 years ago

School starts in 45 minutes and you live 17 miles from school. What average speed (in miles per hour) do you need to travel in o

Arada [10]

It would be 22.67mph

3 0

3 years ago

Solve the system using elimination.<br><br> 2x + 3y = 17<br> x + 5y = 19

ale4655 [162]

$\left\{\begin{array}{ccc}2x+3y=17\\x+5y=19&|\text{multiply both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}2x+3y=17\\-2x-10y=-38\end{array}\right}\qquad\text{add both sides of equations}\\.\qquad\qquad-7y=-21\qquad\text{divide both sides by (-7)}\\.\qquad\qquad \boxed{y=3}\\\\\\\text{Substitute the value of y to the second equation}\\\\x+5(3)=19\\\\x=15=19\qquad\text{subtract 15 from both sides}\\\\\boxed{x=4}\\\\Answer:\ x=4\ and\ y=3.$

5 0

2 years ago

How are percents greater than 100 used in real world contexts

Paul [167]

Used show you have more than what is needed. Example is you need 6 slices of pizza for all your friends but have 7 slices you have more than is needed.

3 0

2 years ago

What the recursive formula for the sequence

klemol [59]

$\bf n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a_n=2-5(n-1)\implies a_n=\stackrel{\stackrel{a_1}{\downarrow }}{2}+(n-1)(\stackrel{\stackrel{d}{\downarrow }}{-5})$

so, we know the first term is 2, whilst the common difference is -5, therefore, that means, to get the next term, we subtract 5, or we "add -5" to the current term.

$\bf \begin{cases} a_1=2\\ a_n=a_{n-1}-5 \end{cases}$

just a quick note on notation:

$\bf \stackrel{\stackrel{\textit{current term}}{\downarrow }}{a_n}\qquad \qquad \stackrel{\stackrel{\textit{the term before it}}{\downarrow }}{a_{n-1}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{current term}}{a_5}\qquad \quad \stackrel{\textit{term before it}}{a_{5-1}\implies a_4}~\hspace{5em}\stackrel{\textit{current term}}{a_{12}}\qquad \quad \stackrel{\textit{term before it}}{a_{12-1}\implies a_{11}}$

8 0

3 years ago