Write an expression that represents 5 squared.

Mathematics

1 answer:

Korvikt [17]3 years ago

4 0

5 squared is 5^2.

Squared means the power of two, so exponent two.

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Solve the inequality −14a≥42, and write the solution in interval notation.

PSYCHO15rus [73]

The solutions to the inequality are (-∞, -3] or a ≤ -3 if the inequality −14a≥ 42 graph is shown in the picture.

<h3>What is inequality?</h3>

It is defined as the expression in mathematics in which both sides are not equal they have mathematical signs either less than or greater than known as inequality.

We have an inequality:

−14a ≥ 42

-a ≥ 3

a ≤ -3

a ∈ (-∞, -3]

Thus, the solutions to the inequality are (-∞, -3] or a ≤ -3 if the inequality −14a≥ 42 graph is shown in the picture.

Learn more about the inequality here:

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If cos Θ = square root 2 over 2 and 3 pi over 2 < Θ < 2π, what are the values of sin Θ and tan Θ? sin Θ = square root 2 ov

densk [106]

Answer:

$\huge\boxed{\sin\theta=-\dfrac{\sqrt2}{2};\ \tan\theta=-1}$

Step-by-step explanation:

We have:

$\\cos\theta=\dfrac{\sqrt2}{2},\ \dfrac{3\pi}{2}$

For sine use:

$\sin^2x+\cos^2x=1\to\sin^2x=1-\cos^2x$

Substitute:

$\sin^2\theta=1-\left(\dfrac{\sqrt2}{2}\right)^2\\\\\sin^2\theta=1-\dfrac{(\sqrt2)^2}{2^2}\\\\\sin^2\theta=1-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4}{4}-\dfrac{2}{4}\\\\\sin^2\theta=\dfrac{4-2}{4}\\\\\sin^2\theta=\dfrac{2}{4}\to\sin\theta=\pm\sqrt{\dfrac{2}{4}}\\\\\sin\theta=\pm\dfrac{\sqrt2}{\sqrt4}\\\\\sin\theta=\pm\dfrac{\sqrt2}{2}$