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3 years ago

9

Write an expression that represents 5 squared.

1 answer:

Korvikt [17]3 years ago

4 0

5 squared is 5^2.

Squared means the power of two, so exponent two.

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The student council sold jars of mixed nuts at their bazaar they were given 40 empty jars. They paid $19.60 for the nuts and $11

Alex Ar [27]

Answer:

$\$1.75$

Step-by-step explanation:

Total amount paid for the nuts is $19.60

Total amount paid for the ribbons is $11.20

Profit made on each jar is 98￠= $0.98

Cost price of the nuts and ribbon for the 40 jars is $19.6+11.2=\$30.8$

Cost price for nuts and ribbonn for one jar = $\dfrac{30.8}{40}=\$0.77$

Selling price is the sum of the cost price and profit.

Selling price for one jar = $0.77+0.98=\$1.75$

They charged $\$1.75$ for each jar.

3 0

3 years ago

Someone please help me with this question I need the answer plsss

kow [346]

Answer:

6

Step-by-step explanation:

The slope is: $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$ . In this case, for the numerator you get 30. For the denominator you get 5. Divide 30/5 to get 6 as your final slope.

Hope it helps!

5 0

3 years ago

Read 2 more answers

Help a brother out.ill give brainlist

julsineya [31]

$\text{a. cm}^2\\\\\text{b. cm}^3\\\\\text{c. cm}\\\\\text{d. cm}^2\\\\\text{e. cm}^3\\$

3 0

3 years ago

Can someone help me on 13<br><br><br><br> Plz

Ad libitum [116K]

10(3) + 3 = 33 times in 2 minutes
10(120) + 3 = 1203 times in 2 hours

7 0

3 years ago

Read 2 more answers

The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

5 0

3 years ago