Let thw second integer be x
then the first = 2x
and the third integer is = 6+x
their sum = 74
x+2x+6+x = 74
4x +6 = 74
4x = 74-6 =68
x =68÷4
x = 17
then the first integer is 2×17 = 34
the third integer is 17+6 = 23
the integers are 17 , 23 and 34
Answer:
4/8
Step-by-step explanation:
y^2-y^1/ x^2-x^1
-1-3/ -4-4 =-4/-8
I hope this helped!!
<span>5999382000 is the answer</span>
Answer:
5
Step-by-step explanation:
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11 because if you count the spaces between the two places, the answer would be 11.
