Answer:
For both sets of data, the median is equal to the mean.
The interquartile range (IQR) is greater for M's classes than J's classes.
Step-by-step explanation:
<u>J's Classes:</u>
23, 25, 27, 28, 32
Median: 27
Mean: 27
Mean Absolute Deviation: 2.4
Interquartile Range: 3
<u>M's Classes:</u>
20, 24, 26, 29, 31
Median: 26
Mean: 26
Mean Absolute Deviation: 3.2
Interquartile Range: 5
Answer:
the function is continuous from the left at x=1 and continuous from the right at x=0
Step-by-step explanation:
a function is continuous from the right , when
when x→a⁺ lim f(x)=f(a)
and from the left when
when x→a⁻ lim f(x)=f(a)
then since the functions presented are continuous , we have to look for discontinuities only when the functions change
for x=0
when x→0⁺ lim f(x)=lim e^x = e^0 = 1
when x→0⁻ lim f(x)=lim (x+4) = (0+4) = 4
then since f(0) = e^0=1 , the function is continuous from the right at x=0
for x=1
when x→1⁺ lim f(x)=lim (8-x) = (8-0) = 8
when x→1⁻ lim f(x)=lim e^x = e^1 = e
then since f(1) = e^1=e , the function is continuous from the left at x=1
The standard error of the mean is 128.125.
The formula for standard error is:
With our information, we have:
It's is 895 because u add 4 with 1 so yeah it's 895
