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2 years ago

Please help I can’t figure this out!

Mathematics

1 answer:

Monica [59]2 years ago

4 0

Explanation:

All values in the x-column get filled with -2.

The graph is the vertical line, x = -2.

You are told x=-2. There is nothing to figure out. The value of y is irrelevant.

That equation describes a vertical line. The points on the line have x-coordinate -2, and any (every) y-coordinate.

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What is the equation of the circle with center (4, 4) that passes through the point (10, 14)? HELP MEEEEE PLEASE

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Answer:

The equation of the circle can be written as:

$\left(x-4\right)^2+\left(y-4\right)^2=136$

Step-by-step explanation:

The general equation of a circle with center $(h,k)$ and radius $r$ is:

$\left(x-h\right)^2+\left(y-k\right)^2=r^2$

In our example, we know $\left(h,k\right)=\left(4,4\right)$ , as we just have to make sure we need determine $\:r^2$ .

$\left(x-4\right)^2+\left(y-4\right)^2=r^2\:\:$

As the circle passes through (10, 14), that pair of values for x and y must satisfy the equation. So we have:

$\left(10-4\right)^2+\left(14-4\right)^2=r^2$

$\mathrm{Switch\:sides}$

$r^2=\left(10-4\right)^2+\left(14-4\right)^2$

$r^2=6^2+10^2$

$r^2=36+100$

$r^2=136$

Thus the equation of the circle can be written as:

$\left(x-4\right)^2+\left(y-4\right)^2=136$

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