Answer: 110
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
pilot flew a 400-mile flight in 2.5 hours flying into the wind . Flying the same rate and with the same wind speed, the return trip took only 2hours with a tailwind
The speed can be defined as the ratio distance over time, but in this case the pilot is flying at the speed of the plane as well of speed of the wind. We can denote speed of plane as "s" and speed of the wind as "k"
Then the speed of the plane=(s-k) this is because it is moving in the opposite direction of the wind.
But From the question, the plane distance=400mile and the corresponding time =2.5 h
Then the speed of the plane=(s-k) =400mile/2.5
=160mph
By the time it return from trip, the speed the plane flew with is (s+k) because the wind is at the rear.
From the question, the plane distance=400mile and the corresponding time =2 h
Then (s+k)= (400/2)
(s+k)=200mph
Replace 7 for the variable, t. N= 2000(2(7))= 28000
Answer:
7.5 +9.63.
7.5+9.63. + N
17.13N
is the answer
Step-by-step explanation:
Answer:
0.395 kilometers
Step-by-step explanation:
Please consider the complete question.
On Martin's first stroke, his golf ball traveled 4/5 of the distance to the hole. On his second stroke, the ball went into the hole. Martin was standing 79 meters from the hole as he took his second stroke. How many kilometers from the hole was Martin when he started?
Let x represent the distance between hole and start point.
In 1st stroke ball traveled 4/5 of the distance, so 1/5 of the distance was remaining from 2nd stroke to hole. This means the 1/5 of whole distance between start point and hole is equal to 79 meters.
We can represent this information in an equation as:
Since our distance is in meters, so we will convert 395 meters into kilometers by dividing by 1000.
Therefore, Martin was 0.395 kilometers from the hole, when he started.
