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3 years ago

Two congruent squares are joined to make a rectangle. The perimeter of the rectangle is 96 cm.

2 answers:

4 0

Answer is C.
288 cm2

----------------------------------------
96 / 2 = 48

each square has side = 12

so new rectangle has L = 24, W = 12

A = 12 x 24 = 288

loris [4]3 years ago

3 0

D.
144 cm2
Two congruent squares are joined to make a rectangle. The perimeter of the rectangle is 96 cm.

What is the area of the rectangle?

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(15 qt/hr) x (1/4 gal/qt) x (1/60 hr/min) =

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2 years ago

A triangle in the coordinate plane has vertices ????(0,10), ????(−8,8), and ????(−3,5). Is it a right triangle? If so, at which

GaryK [48]

Answer:

It is a right triangle, the right angle is at the point (-3, 5)

Step-by-step explanation:

The first step is to locate the points of the vertices in a plane, in this case they are (0.10), (-8.8) and (-3.5). The desmostration of this is shown in the attached image.

As we can see it is formed a right triangle (the figure outlined in red), and the rigth angle is the one at the point (-3,5).

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3 years ago

A pen company averages 1.2 defective pens per carton produced (200 pens). The number of defects per carton is Poisson distribute

nlexa [21]

Answer:

a. P(x = 0 | λ = 1.2) = 0.301

b. P(x ≥ 8 | λ = 1.2) = 0.000

c. P(x > 5 | λ = 1.2) = 0.002

Step-by-step explanation:

If the number of defects per carton is Poisson distributed, with parameter 1.2 pens/carton, we can model the probability of k defects as:

$P(k)=\frac{\lambda^{k}e^{-\lambda}}{k!}= \frac{1.2^{k}\cdot e^{-1.2}}{k!}$

a. What is the probability of selecting a carton and finding no defective pens?

This happens for k=0, so the probability is:

$P(0)=\frac{1.2^{0}\cdot e^{-1.2}}{0!}=e^{-1.2}=0.301$

b. What is the probability of finding eight or more defective pens in a carton?

This can be calculated as one minus the probablity of having 7 or less defective pens.

$P(k\geq8)=1-P(k$

$P(0)=1.2^{0} \cdot e^{-1.2}/0!=1*0.3012/1=0.301\\\\P(1)=1.2^{1} \cdot e^{-1.2}/1!=1*0.3012/1=0.361\\\\P(2)=1.2^{2} \cdot e^{-1.2}/2!=1*0.3012/2=0.217\\\\P(3)=1.2^{3} \cdot e^{-1.2}/3!=2*0.3012/6=0.087\\\\P(4)=1.2^{4} \cdot e^{-1.2}/4!=2*0.3012/24=0.026\\\\P(5)=1.2^{5} \cdot e^{-1.2}/5!=2*0.3012/120=0.006\\\\P(6)=1.2^{6} \cdot e^{-1.2}/6!=3*0.3012/720=0.001\\\\P(7)=1.2^{7} \cdot e^{-1.2}/7!=4*0.3012/5040=0\\\\$

$P(k$

c. Suppose a purchaser of these pens will quit buying from the company if a carton contains more than five defective pens. What is the probability that a carton contains more than five defective pens?

We can calculate this as we did the previous question, but for k=5.

$P(k>5)=1-P(k\leq5)=1-\sum_{k=0}^5P(k)\\\\P(k>5)=1-(0.301+0.361+0.217+0.087+0.026+0.006)\\\\P(k>5)=1-0.998=0.002$

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3 years ago

ANSWER ASAP PLS 20 POINTS! Which graph represents the piecewise defined function? y= {3 if x<-2 0 if x=1 -1 if x>1

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Answer:

It is the third option. (the one which has a black point at X=1, Y=1)

Step-by-step explanation:

For simplicity what you should do is, you should satisfy the second condition that is, y=0 if x=1.

Here only the third option is satisfying this condition.

Whenever there is is a white circle or a white point it means that the point does not satisfy the condition and the the function is not defined at that point. And the black point means that the circle is defined at that point and satisfies the condition.

Henceforth, the correct answer is the third option.

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3 years ago

One hundred and sixty-two thousandths as a decimal

lapo4ka [179]

Answer:

100.062

Step-by-step explanation:

100 + 62/1000 = 100 + 0.062 = 100.062

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2 years ago

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