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3 years ago

An experiment consist of drawing 1 card from a standard 52 -card deck. Let E be the event that card drawn is a 2. Find P(E').

1 answer:

5 0

The sum of the probabilities of an event E and its complement E' is 1,

that is P(E)+P(E')=1, where E' is "not E".

The event E can happen in 4 ways, because there are four 2's that can be drawn.

P(E)=n(E)/52=4/52=0.08

P(E')=1-P(E)=1-0.08=0.92

Answer: 0.92

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Answer:

112in

Step-by-step explanation:

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3 years ago

Check all apply 3x+4=10

garri49 [273]

Answer:

Solution is x=2. sorry if this is not what you are looking for!

Step-by-step explanation:

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3 years ago

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The airplane in the scale drawing has a wingspan of a feet and a tail span of b feet. If the tailspin in the drawing is 2 inches

xeze [42]

Correct answer is: actual wingspan of airplane is 6 inches.

Solution:-

We are given that wingspan is 'a' feet and tail span is 'b' feet in a scale drawing.

And we are also given that tail span is 2 inches that is b=2 inches and $\frac{a}{b}=3$

Let us plugin the b value in above equation.

$\frac{a}{2}=3$

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a=3X2=6 inches.

Hence actual wingspan of airplane is 6 inches.

7 0

3 years ago

I just need no. a please help me to prove this.

OleMash [197]

Answer: see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π and cos A = cos B · cos C

scratchwork:

A + B + C = π

A = π - (B + C)

cos A = cos [π - (B + C)] Apply cos

= - cos (B + C) Simplify

= -(cos B · cos C - sin B · sin C) Sum Identity

= sin B · sin C - cos B · cos C Simplify

cos B · cos C = sin B · sin C - cos B · cos C Substitution

2cos B · cos C = sin B · sin C Addition

$2=\dfrac{\sin B\cdot \sin C}{\cos B \cdot \cos C}$ Division

2 = tan B · tan C

$\text{Use the Sum Identity:}\quad \tan(B+C)=\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}$

<u>Proof LHS → RHS</u>

Given: A + B + C = π

Subtraction: A = π - (B + C)

Apply tan: tan A = tan(π - (B + C))

Simplify: = - tan (B + C)

$\text{Sum Identity:}\qquad \qquad \qquad =-\bigg(\dfrac{\tan B+\tan C}{1-\tan B\cdot \tan C}\bigg)$

Substitution: = -(tan B + tan C)/(1 - 2)

Simplify: = -(tan B + tan C)/-1

= tan B + tan C

LHS = RHS: tan B + tan C = tan B + tan C $\checkmark$

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3 years ago

Louis wants to carpet the rectangular floor of his basement. The basement has an area of 500 square feet. The width of the basem

Mazyrski [523]

Answer:

The correct answer is the length is 10 feet and width is 2 feet respectively.

Step-by-step explanation:

Let length of the rectangular floor of Louis' basement be l feet and width be $\frac{l}{5}$ feet respectively.

Area of the basement floor is given to be 500 square feet.

Therefore according to the given problem,

l × $\frac{l}{5}$ = 500

⇒ $l^{2}$ = 100

⇒ l = 10 ; [length cannot be negative]

⇒ b = 2

Thus the length and width be 10 feet and 2 feet respectively.

4 0

3 years ago