What is the value of (5!)/3!*2
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Answer:
inside
Step-by-step explanation:
All of the points on the circle are at distance 25 units from the center. If the questionable point is closer to the center than that, it is inside the circle.
The distance formula can be used.
d = √((x2 -x1)^2 +(y2 -y1)^2)
d = √((5 -(-5))^2 +(-24 -(-8))^2) = √(10^2 +(-16)^2) = √(100 +256) = √356
d ≈ 18.9
The point (5, -24) is inside the circle centered at (-5, -8) with radius 25.
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The equation of the circle is equivalent to d=25 using (x1, y1) as the center. It is usually written without the radical:
(x -(-5))^2 +(y -(-8))^2 = 25^2
(x +5)^2 +(y +8)^2 = 625
