1)
c^2 < a^2 + b^2 = acute
<span>c^2 > a^2 + b^2 = obtuse</span>
<span>c^2 = a^2 + b^2 = right</span>
so
c^2 = 47^2 = 2209
a^2 + b^2 = 20^2 + 34^2 = 400 + 1156 = 1556
<span> 2209 >1156</span>
c^2 > a^2 + b^2 = obtuse
answer is B. obtuse
2)
<A = 90, <B = <C = 45
AC = AB = 12
12^2 + 12^2 = 2 (12^2)
BC = 12√2
answer is C. 12√2 ft
3)
a square cut into 2 equal triangles (2 isosceles triangles)
So it's 45 45 90 right triangle
if hypo = 34 then side = 17√2
answer is C. 17√2 inches
Answer:1,2,5
Step-by-step explanation:
Answer:
Step-by-step explanation:
Solve for the mean (average) of the five test scores.
Subtract that mean from each of the five original test scores. Square each of the differences.
Find the mean (average) of each of these differences you found in Step 2.
Take the square root of this final mean from #3. This is the standard deviation.
<h3><u>Answer:</u></h3>

<h3><u>Solution</u><u>:</u></h3>
we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

Here,
- hypotenuse = 23 feet
= 76°- Value of Sin
= 0.97 - Perpendicular = ?





ㅤㅤㅤ~<u>H</u><u>e</u><u>n</u><u>c</u><u>e</u><u>,</u><u> </u><u>the </u><u>distance </u><u>from </u><u>the </u><u>top </u><u>of </u><u>the </u><u>ladder </u><u>to </u><u>the </u><u>ground </u><u>is </u><u>2</u><u>2</u><u>.</u><u>3</u><u>2</u><u> </u><u>feet </u><u>!</u>

Answer:
OK
Step-by-step explanation:
LOL SO WHAT I . DID
IS ik the qudrents and just ask siri maybe she will help but i got qudrent 3