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saveliy_v [14]
3 years ago
13

Sam found a tent in his garage, and he needs to find the center height. The sides are both 5 feet long, and the bottom is 6 feet

wide. What is the center height of Sam’s tent, to the nearest tenth?
Mathematics
2 answers:
sergiy2304 [10]3 years ago
4 0

Answer:

4 feet

Step-by-step explanation:

Sam’s tent, to the nearest tenth

xenn [34]3 years ago
4 0

Answer:

4 feet

Step-by-step explanation:

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HELP ME PLEASE! HALF-DONE ANSWERS WILL BE DELETED! 15 POINTS!
Leni [432]

Answer:

G) Yes, because the plots and the linear model both align to produce a similar calculated sum.

H) I need to see the data table again for step 2d.

Step-by-step explanation:

1.) You scatter plot should be off by 6.97, since that was the first difference in your data table set of terms.

Basically subtract all of the GPAs from the Hours in the table.

Ex). Hours - GPA = Difference

or like before,

      9.2 - 2.23 = 6.97

Do the rest of the numbers like this then plot the answers.  I'd advise you plot your second set of scatter plot points in a different color.

6 0
3 years ago
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Division of decimals
Ludmilka [50]

Answer:

At Least 20

85÷3.5

=24.28

So at least 20.

If I'm wrong, I'm sorry.

4 0
3 years ago
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In a random sample of 500 handwritten zip code digits, 464 were read correctly by an optical character recognition (OCR) system
In-s [12.5K]

Answer:

z= 2.38

P = 0.008656

Step-by-step explanation:

Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072

We formulate our null and alternate hypothesis as

H0 =  0.9 ;       H0 > 0.9

The degree of confidence = 90%

z₀.₀₅ = 1.645 for  α= 0.05

We use the test statistic

z=  x- np/√npq

z= 466-500 *0.9/ √500 * 0.9(1-0.9)

z= 466- 450/ √45

z= 16/6.7082

z= 2.38

As the calculated value of z= 2.38  is greater than α =1.645 so we reject H0.

If H0 is true the P value is calculated as

P = 1- Ф( 2.38)

P = 1-0.991344=0.008656

7 0
3 years ago
Re-write the quadratic function below in Standard Form<br> y = 9(x - 1)(x + 3)
Maksim231197 [3]
Y=9(x^2+3x-x-3)
y=9(x^2+2x-3)
y=9x^2+18x-27
4 0
3 years ago
Find the work required to move an object in the force field F = e^x + y (1, 1, z) along the straight line from A(0, 0, 0) to B(-
DENIUS [597]

\vec F(x,y,z)=(e^x+y)(1,1,z)

is conservative if we can find a scalar function f such that \nabla f=\vec F. This would require

f_x=e^x+y

f_y=e^x+y

f_z=(e^x+y)z

Integrating both sides of the first equation wrt x gives

f(x,y,z)=e^x+xy+g(y,z)

Differentiating both sides of this wrt y gives

f_y=x+g_y=1\implies g_y=1-x\implies g(y,z)=y-xy+h(z)

but we assumed g was a function of y and z, independent of x. So there is no such f and \vec F is not conservative.

To find the work, first parameterize the path (call it C) by

\vec r(t)=(1-t)(0,0,0)+t(-4,5,-5)=(-4t,5t,-5t)

for 0\le t\le1. Then

\vec r'(t)=(-4,5,-5)

and the work is given by the line integral,

W=\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\int_0^1(e^{-4t}+5t,e^{-4t}+5t,-(e^{-4t}+5t)5t)\cdot(-4,5,-5)\,\mathrm dt

W=\displaystyle\int_0^1(125t^2+5t+(25t+1)e^{-4t})\,\mathrm dt=\boxed{\frac{2207}{48}-\frac{129}{16e^4}}

8 0
3 years ago
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