Answer:
G) Yes, because the plots and the linear model both align to produce a similar calculated sum.
H) I need to see the data table again for step 2d.
Step-by-step explanation:
1.) You scatter plot should be off by 6.97, since that was the first difference in your data table set of terms.
Basically subtract all of the GPAs from the Hours in the table.
Ex). Hours - GPA = Difference
or like before,
9.2 - 2.23 = 6.97
Do the rest of the numbers like this then plot the answers. I'd advise you plot your second set of scatter plot points in a different color.
Answer:
z= 2.38
P = 0.008656
Step-by-step explanation:
Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072
We formulate our null and alternate hypothesis as
H0 = 0.9 ; H0 > 0.9
The degree of confidence = 90%
z₀.₀₅ = 1.645 for α= 0.05
We use the test statistic
z= x- np/√npq
z= 466-500 *0.9/ √500 * 0.9(1-0.9)
z= 466- 450/ √45
z= 16/6.7082
z= 2.38
As the calculated value of z= 2.38 is greater than α =1.645 so we reject H0.
If H0 is true the P value is calculated as
P = 1- Ф( 2.38)
P = 1-0.991344=0.008656
Y=9(x^2+3x-x-3)
y=9(x^2+2x-3)
y=9x^2+18x-27

is conservative if we can find a scalar function
such that
. This would require



Integrating both sides of the first equation wrt
gives

Differentiating both sides of this wrt
gives

but we assumed
was a function of
and
, independent of
. So there is no such
and
is not conservative.
To find the work, first parameterize the path (call it
) by

for
. Then

and the work is given by the line integral,

