Answer:
G) Yes, because the plots and the linear model both align to produce a similar calculated sum.
H) I need to see the data table again for step 2d.
Step-by-step explanation:
1.) You scatter plot should be off by 6.97, since that was the first difference in your data table set of terms.
Basically subtract all of the GPAs from the Hours in the table.
Ex). Hours - GPA = Difference
or like before,
9.2 - 2.23 = 6.97
Do the rest of the numbers like this then plot the answers. I'd advise you plot your second set of scatter plot points in a different color.
Answer:
z= 2.38
P = 0.008656
Step-by-step explanation:
Here n= 500 and p~= 464/500= 0.928 and q`= 1- 0.928 = 0.072
We formulate our null and alternate hypothesis as
H0 = 0.9 ; H0 > 0.9
The degree of confidence = 90%
z₀.₀₅ = 1.645 for α= 0.05
We use the test statistic
z= x- np/√npq
z= 466-500 *0.9/ √500 * 0.9(1-0.9)
z= 466- 450/ √45
z= 16/6.7082
z= 2.38
As the calculated value of z= 2.38 is greater than α =1.645 so we reject H0.
If H0 is true the P value is calculated as
P = 1- Ф( 2.38)
P = 1-0.991344=0.008656
Y=9(x^2+3x-x-3)
y=9(x^2+2x-3)
y=9x^2+18x-27
is conservative if we can find a scalar function 
such that 
. This would require
Integrating both sides of the first equation wrt 
gives
Differentiating both sides of this wrt 
gives
but we assumed 
was a function of and 
, independent of . So there is no such and 
is not conservative.
To find the work, first parameterize the path (call it 
) by
for 
. Then
and the work is given by the line integral,
