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ch4aika [34]
4 years ago
9

Find the slope intercept form of the equation that passes through the given point and is parallel to the given line (-3,2) and y

=x-6
Mathematics
1 answer:
posledela4 years ago
8 0

Answer:

y = x + 5

Step-by-step explanation:

The equation of any two parallel lines differ by a constant.

That is, the equation of the line parallel to the line y = ax + b is y = ax + c.

The equation of the line is given to be: y  = x - 6.

Therefore, the equation of the parallel line would be:

y = x + b

Since, the point (-3, 2) passes through the point, we can substitute in the equation to determine the value of 'b'.

Hence, 2 = - 3 + b

So. b = 5.

Therefore, the equation of the line becomes:

y = x + 5

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3 years ago
-5 is to the _____ of 0.<br>Answer early pls​
Norma-Jean [14]

\Huge\boxed{Hi~there!}

On a number line, -5 is to the left of 0.

Remember, on a number line, positive numbers (including fractions, decimals and surds) are to the right of 0:

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0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

Negative numbers (including rational and irrational numbers) are to the left of 0:

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      -8      -7        -6     -5         -4     -3   -2    -1 0

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3 0
3 years ago
A line segment has endpoints at (8, 3) and (2,5). What would be the equation of this line's perpendicular bisector?
ale4655 [162]

Answer:

y  = −1/3x+17/3

Step-by-step explanation:

The line segment has slope -1/3. This means that any line perpendicular to it will have a slope of 3 (negative reciprocal)

Any line that bisects the line segment will pass through its midpoint. The midpoint is (5,4)

Midpoint formula: ( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2} )

So perpendicular bisector of this line  is simply a line with slope −1/3 that passes through point (5, 4)

y - 4 = -1/3 (x-5)=

y  =  −1/3x+17/3

7 0
3 years ago
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