Looks good! You have the right answers.
However, the graph for 12 and 15 is inaccurate! Because he starts from a stop sign/stop light, the graph's speed should start from the origin!
Not to confuse you or anything, but this means the graph does not follow the description of the problem. Please let your teacher know so s/he can fix the worksheet.
Answer:
B (5, 13)
Step-by-step explanation:
9x + 4y = 97
9x + 6y = 123
To solve by elimination, we want to <em>eliminate</em> a variable. To do this, we must make one variable cancel out.
First, we can see that both equations have 9x. To cancel out x, we must make <em>one</em> of the 9x's <em>negative</em>. To do this, multiply <em>each term</em> in the equation by -1.
-1(9x + 6y = 123)
-9x - 6y = -123
This is one of your equations. Set it up with your other given equation.
9x + 4y = 97
-9x - 6y = -123
Imagine this is one equation. Since every term is negative, you will be subtracting each term.
9x + 4y = 97
-9x - 6y = -123
___________
0x -2y = -26
-2y = -26
To isolate y further, divide both sides by -2.
y = 13
Now, to find x, plug y back into one of the original equations.
9x + 4(13) = 97
Multiply.
9x + 52 = 97
Subtract.
9x = 45
Divide.
x = 5
Check your answer by plugging both variables into the equation you have not used yet.
-9(5) - 6(13) = -123
-45 - 78 = -123
-123 = -123
Your answer is correct!
(5, 13)
Hope this helps!
Answer: (12,0)
Steps:
First, put the equation in slope-intercept form.
y=mx+b
1.5x + 4.5y =18
Subtract 1.5x from both sides.
4.5y =-1.5x +18
Divide both sides by 4.5 to isolate y.
y = -1/3x + 4
Then replace y with 0 because the point for the x-intercept is exactly on the x-axis so the y=0.
0 = -1/3x + 4
Subtract 4 from both sides
-4 = -1/3x
Divide both sides by -1/3 to isolate the x
12=x
Answer:
I disagree
'No it won;t
Step-by-step explanation:
Given the inequality functions;
-2(3 – x) > 2x – 6
Open the parenthesis
-2(3) -2(-x) > 2x - 6
-6 + 2x > 2x - 6
Collect like terms
2x-2x > -6 + 6
0x > 0
x > 0/0
<em>The value of x does not exist on any real number. I disagree with my friend since the value of x is an indeterminate function. If the inequality were ≥, it won't change anything as the value of x won't still exist on any real number </em>
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