Answer: D) ABCD ∼ EFGH
Step-by-step explanation:
From the given picture,
In parallelogram ABCD, ∠A= 80° .
In parallelogram EFGH, ∠E= 100° .
Since the sum of two adjacent angles in a parallelogram is 180°.
So, ∠A + ∠B = 180°
⇒ ∠B = 180° -∠A = 180°- 80° = 100°
So, ∠B = 100°
Similarly in parallelogram EFGH, ∠ E= 80° .
Also, the opposite angles of a parallelogram are equal,
∠A =∠C= 80° and ∠B=∠D=100°
∠E =∠G= 80° and ∠F=∠H=100°
So, the corresponding angles of both parallelograms are equal.
That means they are similar.
So the required similarity statement : ABCD ∼ EFGH
Hence, the correct option is D.
