Answer:
The speed of the stone just before it hits the ground is 18.54 m/s
Explanation:
Given that,
Initial speed of the stone, u = 8 m/s
The stone is thrown downward from a height of 14 m
We need to find the speed of the stone just before it hits the ground. It can be calculated using third equation of motion as :
v is the speed of the stone just before it hits the ground
v = 18.54 m/s
So, the speed of the stone just before it hits the ground is 18.54 m/s. Hence, this is the required solution.
Answer:
0.763 m
Explanation:
Intensity I = power P ÷ area A of exposure (spherical area of propagation)
I = P/A
A = P/I
Power = 10.0 W
Intensity = 1.39 W/m^2
A = 10/1.39 = 7.19 m^2
Area A = 4¶r^2
7.19 = 4 x 3.142 x r^2
7.19 = 12.568r^2
r^2 = 7.19/12.568 = 0.57
r = 0.753 m
The letter “j” is never found on the periodic table. As for numbers, there’s an infinite amount
Answer:
286.7 m
Explanation:
So we are assuming the PE of the falcon is converted to KE
KE = PE
1/2 (.480)(75)^2 = .480 (9.81)(h ) solve for h = 286.7 m
Answer: = . /
Explanation:
The acceleration is
= − 0
In our case, the initial velocity has minus sign.
Thus,
=
− (−0)
=
+ 0
Substituting
0 =
2
(
+
0
) −
=
2
+
0
2
−
Thus,
0
2
=
2
−
So,
0 = −
= 8.62 −
12.9
8.25 = 7.06 m/s
Answer: = . /
