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Anton [14]
3 years ago
7

Define the terms solute, solvent, and solubility. Describe two factors that influence solubility.

Physics
1 answer:
wolverine [178]3 years ago
6 0
Solute - the distance dissolved in a solution . 
solvent - able to dissolve other substances . 
solubility - dissolve in a solvent.
factor #1: temperature .
factor#2: polarity.
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When large amplitude sound vibrates the ear significantly, a _______ results.
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D loud sound

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3 years ago
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Water enters an ice machine at 55F and leaves as ice at 25F. If the COP of the ice machine is 3.7 during this operation, determi
boyakko [2]

Answer:

The required power is P_i = 0.2692 \ hp

Explanation:

From the question we are told that

   The temperature of the water entering ice machine is T_1 =  55 ^o F

    The temperature of the water leaving is T_2 = 25 ^oF

    The COP of the ice machine is COP= 3.7

    The production rate of an ice  \r m = 15.0 \ lbm /hr

    The energy that needs to removed from each lbm of water at 55 F is E = 169 Btu

Generally the cooling load of the ice machine is mathematically represented as

       \r Q_L =  \r m * E

      \r Q_L =15 * 169

=>  \r Q_L = 2535 \ Btu/h

Generally the COP of the ice machine is mathematically represented as

       COP =  \frac{\r Q_L}{P_i}

Here P_i is the net power  input needed to successfully run the ice machine

So  

     3.7 =  \frac{2535}{P_i}

=>   P_i = 685 \  Btu/h

Converting to horsepower

      P_i = \frac{685}{2545}

=>   P_i = 0.2692 \ hp

     

3 0
3 years ago
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6 0
3 years ago
In general relativity, gravitational red shift is caused by
kvasek [131]
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7 0
3 years ago
A fluid is flowing with an average speed of 1.5 m/s through a tube that has a radius of 2.0 mm and is 18 cm long. The drop in pr
Ymorist [56]

Answer:

μ = 0.038 Pa.s

Explanation:

Given that

V= 1.5 m/s

r= 2 mm

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If we assume that flow inside the tube is laminar ,then the pressure drop ΔP given as

\Delta P=\dfrac{32\mu LV^2}{d^2}

\Delta P=\dfrac{32\mu LV^2}{d^2}

\mu = \dfrac{\Delta P D^2}{LV^2}

\mu = \dfrac{967\times 0.004^2}{0.18\times 1.5^2}\ Pa.s

μ = 0.038 Pa.s

The viscosity of the fluid = 0.038 Pa.s

5 0
4 years ago
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