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spin [16.1K]
4 years ago
10

Simplify 7/10 - 1/10

Mathematics
2 answers:
ololo11 [35]4 years ago
7 0

Answer:3/5

Step-by-step explanation:

Because you subtract then simplify

RSB [31]4 years ago
6 0

Answer:3/5

Step-by-step explanation:

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The amounts of time per workout an athlete uses a stairclimber are normally​ distributed, with a mean of 24 minutes and a standa
Elodia [21]

Answer:

(a) The probability that a randomly selected athlete uses a stairclimber for​  less than 19 ​minutes is 0.2388.

(b) The probability that a randomly selected athlete uses a stairclimber for​  between 24 and 33 ​minutes is 0.3997.

(c) The probability that a randomly selected athlete uses a stairclimber for​  more than 40 minutes is 0.0113.

Step-by-step explanation:

We are given that the amounts of time per workout an athlete uses a stairclimber are normally​ distributed, with a mean of 24 minutes and a standard deviation of 7 minutes.

Let X = <u><em>amounts of time per workout an athlete uses a stairclimber</em></u>

So, X ~ Normal(\mu=24,\sigma^{2} =7^{2})

The z-score probability distribution for the normal distribution is given by;

                               Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = mean time = 24 minutes

            \sigma = standard deviation = 7 minutes

(a) The probability that a randomly selected athlete uses a stairclimber for​  less than 19 ​minutes is given by  P(X < 19 minutes)

        P(X < 19 min) = P( \frac{X-\mu}{\sigma} < \frac{19-24}{7} ) = P(Z < -0.71) = 1 - P(Z \leq 0.71)

                                                           = 1 - 0.7612 = <u>0.2388</u>

The above probability is calculated by looking at the value of x = 0.71 in the z table which has an area of 0.7612.

(b) The probability that a randomly selected athlete uses a stairclimber for​  between 24 and 33 ​minutes is given by = P(24 min < X < 33 min)

     P(24 min < X < 33 min) = P(X < 33 min) - P(X \leq 24 min)

     P(X < 33 min) = P( \frac{X-\mu}{\sigma} < \frac{33-24}{7} ) = P(Z < 1.28) = 0.8997

     P(X \leq 24 min) = P( \frac{X-\mu}{\sigma} \leq \frac{24-24}{7} ) = P(Z \leq 0) = 0.50

The above probability is calculated by looking at the value of x = 1.28 and x = 0 in the z table which has an area of 0.8997 and 0.50 respectively.

Therefore, P(24 min < X < 33 min) = 0.8997 - 0.50 = <u>0.3997</u>

(c) The probability that a randomly selected athlete uses a stairclimber for​  more than 40 minutes is given by  P(X > 40 minutes)

        P(X > 40 min) = P( \frac{X-\mu}{\sigma} > \frac{40-24}{7} ) = P(Z > 2.28) = 1 - P(Z \leq 2.28)

                                                           = 1 - 0.9887 = <u>0.0113</u>

The above probability is calculated by looking at the value of x = 2.28 in the z table which has an area of 0.9887.

The event of probability that a randomly selected athlete uses a stairclimber for​  more than 40 minutes is unusual because this probability is less than 5% and any even whose probability is less than 5% is said to be unusual.

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