X = 20
Isolate the variable by dividing each side by factors that don't contain the variable.
x
=
20
Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.
This rule has the form
h(t) = h + v t + (1/2)a*t^2
o o
To adapt this rule to this particular question replace h with 0, as the
o
upward path of the object begins at 0 ft. Replace v with +15 ft/sec.
o
Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.
Then we have the following, with the label F(t):
F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or
F(t) = 15t - 16.1t^2. Thus, Choice D is correct.
Please note: To avoid confusion, please use " ^ " to denote exponentiation:
F(t) = -16t^2 + 15t
The answer is x equals 2.
Since x is across from 148, and arcs opposite inscribed angles = 2×angle, then we can find x first.
We could set the 2 angles equal to 180 or their arcs equal to 360.
360 - (2×148) = x-arc
x-arc = 360 - 296 = 64
x = x-arc ÷2 = 64/2 = 32
Now for angle A we plug in for x:
A = 2x+1 = 2(32)+1 = 65°
