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FrozenT [24]
3 years ago
11

Evaluate: 4[3.1 + 2] 20 20.8 24 Evaluate: 8[1/4] 0 1 2 3

Mathematics
1 answer:
ruslelena [56]3 years ago
8 0

Answer:

answer is 24 :)

Step-by-step explanation:

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Match the following items.
Artyom0805 [142]
1. that is commutative property of addition
a+b=b+a
(-14)+81=81+(-14)

2. multipcative inverse
a times 1/a=1


3. associative property of adition
a+(b+c)=(a+b)+c
101+(29+417)=<span>(101 + 29) + 417 </span>

4. distributive proepty
a(b+c)=ab+ac

5. addative identity
a+0=a
-72+0=-72
4 0
4 years ago
Given: X = r + 2, Y = 2r - 9, and Z = r 2 + 17r + 30. Simplify [X · Y - Z] ÷ X. -r - 24 r - 24 2r2 - 6r - 33 2r2 + 6r + 33
melamori03 [73]

Answer:

r - 24

Step-by-step explanation:

[X · Y - Z] = (r + 2)(2r - 9)] - (r^2 + 17r + 30)

= (2r^2 + 4r - 9r - 18 ) - r^2 - 17r - 30

= 2r^2 - 5r - 18 - r^2 - 17r - 30

= r^2 - 22r - 48

= (r +2)(r - 24)

so

[X · Y - Z] / X

= [(r +2)(r - 24)]  /  (r + 2)

= r - 24

7 0
4 years ago
Read 2 more answers
What is a volume of a cube with the width of 7 inches?
Alisiya [41]

Answer:

343

Step-by-step explanation:

I hope this helps ! Have a good day! <3 :)

4 0
3 years ago
What is 3÷-3 **three divided by negative three**​
Reptile [31]

Answer:

-1

Step-by-step explanation:

It would be -1.

First, you can bring the negative sign outside, calculate 3 divided by 3 (which would be 1). Lastly, bring the negative sign back, so now you would have -1 as your answer.

7 0
3 years ago
How many 4-digit multiples of 21 and 15 are there and 4-digit multiples of either 21 or 15 are there?
salantis [7]

Answer:

943

Step-by-step explanation:

21| 1000

   | ----------

       47 | 13

21-13=8

1000+8=1008

21|9999

  |---------

     476|3

9999-3=9996

1008,1029,...,9996

let n be number of terms

a=1008,d=21,l=9996

9996=1008+(n-1)21

9996-1008=(n-1)21

8988=(n-1)21

n-1=8988/21

n-1=428

n=428+1=429

again 15|1000

            |---------

                66|10

15-10=5

1000+5=1005

15|9999

  | ---------

      666|9

9999-9=9990

1005,1020,...,9990

a=1005,d=15,l=9990

let n be number of terms.

9990=1005+(n-1)15

9990-1005=(n-1)15

8985=(n-1)15

n-1=8985/15

n-1=599

n=599+1=600

21=3×7

15=3×5

L.C.M.=3×5×7=105

105)1000(9

      -945

     ____

         55

105-55=50

1000+50=1050

105)9999(

     -945

   ---------

         549

       - 525

        -------

            24

        -------

9999-24=9975

1050,1155,...,9975

let n be number of terms.

d=105

l=a+(n-1)d

9975=1050+(n-1)105

9975-1050=(n-1)105

8025=(n-1)105

n-1=8925/105

n-1=85

n=85+1=86

so there are 86 multiples of 21 and 15

(A∪B)=A+B-(A∩B)

multiples of 21 or 15=429+600-86=1029-86=943

4 0
3 years ago
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